A square current loop 4.50 cm on each side carries a 490 mA current. The loop is in a 1.50 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction. Part A What is the magnitude of the torque on the current loop? Express your answer in newton-meters to three significant figures. 15. ΑΣΦ T = ? Nm
A square current loop 4.50 cm on each side carries a 490 mA current. The loop is in a 1.50 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction. Part A What is the magnitude of the torque on the current loop? Express your answer in newton-meters to three significant figures. 15. ΑΣΦ T = ? Nm
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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Transcribed Image Text:**Problem Statement:**
A square current loop 4.50 cm on each side carries a 490 mA current. The loop is in a 1.50 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.
**Question (Part A):**
What is the magnitude of the torque on the current loop?
Express your answer in newton-meters to three significant figures.
**Input Box:**
There is a box provided to enter the value of torque (τ) in newton-meters (Nm).
Buttons available for formatting:
- Basic formatting tools (e.g., square root, Greek letters).
- Submission options: "Submit" and "Request Answer".
Expert Solution
Step 1
Given data:
A square current loop
Side length (s) = 4.50 cm = 4.50×10-2 m
Current (A) = 490 mA = 0.490 A
Magnetic field (B) = 1.50 T
The angle between area vector and magnetic field vector (θ) = 30°
Required:
The magnitude of the torque on the current loop
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