Consider the current-carrying wire shown in the figure. The current creates a magnetic field at the point P, which is the center of the arc segment of the wire. If 0 = 30.0°, the radius of the arc is 0.800 m, and the current is 5.00 A, what are the magnitude (in nT) and direction of the field produced at P? magnitude 3.272*10**-* Did you forget to convert from T to nT? nT ℗

Consider the current-carrying wire shown in the figure. The current creates a magnetic field at the point P, which is the center of the arc segment of the wire. If 0 = 30.0°, the radius of the arc is 0.800 m, and the current is 5.00 A, what are the magnitude (in nT) and direction of the field produced at P? magnitude 3.272*10**-* Did you forget to convert from T to nT? nT ℗

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 19P

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Similar questions

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A particle moving downward at a speed of 6.0106 m/s enters a uniform magnetic field that is horizontal and directed from east to west. (a) If the particle is deflected initially to the north in a circular arc, is its charge positive or negative? (b) If B = 0.25 T and the charge-to-mass ratio (q/m) of the particle is 40107 C/kg. what is ±e radius at the path? (c) What is the speed of the particle after c has moved in the field for 1.0105s ? for 2.0s?
One long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along the line (y = 0.280 m, z = 0). (a) Where in the plane of the two wires is the total magnetic field equal to zero? (b) A particle with a charge of 2.00 C is moving with a velocity of 150iMm/s along the line (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle. (c) What If? A uniform electric field is applied to allow this particle to pass through this region undetected. Calculate the required vector electric field.
At a particular instant an electron is traveling west to east with a kinetic energy of 10 keV. Earth's magnetic field has a horizontal component of 1.8105 T north and a vertical component of 5.0105 T down. (a) What is the path of the election? (b) What is the radius of curvature of the path?
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Two long, straight wires are parallel and 25 cm apart. (a) If each wire carries a current of 50 A in the same direction, what is the magnetic force per meter exerted on each wire? (b) Does tire force pull the wires together or push them apart? (c) What happens if the currents flow in opposite directions?
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(a)What is the angle between a wire carrying an 8.00-A current and the 1.20-T field It Is in if 50.0 cm of the wire experiences a magnetic force of 2.40 N? (b) What is the force on the wire If It Is rotated to make an angle of 90° with the field?
The magnitude of the magnetic field 50 cm from a long, thin, straight wire is 8.0T . What is the current through the long wire?
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An electron in a TV CRT moves with a speed of 6.0107 m/s, in a direction perpendicular to Earth's field, which has a strength of 5.0105 T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a collection,)
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