A spring with constant k = 5 N/m hanging from the ceiling is placed at its lower end with an object of 1 N, which causes it to remain in equilibrium. The weight is then pulled 0.5 m above the equilibrium position. and is released with no initial velocity. There is no damping force acting on the system. SI x(t) represents the displacement of the weight, in meters, from the equilibrium point and taking upwards as the positive direction, an equation that describes the position of the weight as a function of time t (in seconds) is: If necessary, use the gravity

University Physics Volume 1
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Chapter1: Units And Measurement
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Problem 83AP: A marathon runner completes a 42.188-km course in 2 h, 30 min, and 12s. There is an uncertainty of...
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A spring with constant k = 5 N/m hanging from the ceiling is placed at its lower end with an object of 1 N, which causes it to remain in equilibrium. The weight is then pulled 0.5 m above the equilibrium position.
and is released with no initial velocity. There is no damping force acting on the system. SI x(t) represents the displacement of the weight, in meters, from the equilibrium point and taking upwards as the
positive direction, an equation that describes the position of the weight as a function of time t (in seconds) is:
If necessary, use the gravity constant g as g = 9.8 m/s2

Possible answer in the images.

 

O a) ¤(t) = 0.25 sen(t/49)
O b) z(t) = 0.25 (evo tetv
O c) z(t) = 0.5 (evão tetveD
49
O d) z(t) = 0.5 cos(t/49)
Transcribed Image Text:O a) ¤(t) = 0.25 sen(t/49) O b) z(t) = 0.25 (evo tetv O c) z(t) = 0.5 (evão tetveD 49 O d) z(t) = 0.5 cos(t/49)
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