A spring is stretched 3 cm by a force of 6 N. Thus, according to Hooke's Law, the spring DO = 200 N. Assume as usual, that r = 0 is the equilibrium position. constant is k 0.03 A mass of 8 kg is now attached to the end of the spring, and it is set in motion with initial position xo = 0 and with initial velocity 10 (m) to the left. ( So, v(0) = -10(m).)

A spring is stretched 3 cm by a force of 6 N. Thus, according to Hooke's Law, the spring DO = 200 N. Assume as usual, that r = 0 is the equilibrium position. constant is k 0.03 A mass of 8 kg is now attached to the end of the spring, and it is set in motion with initial position xo = 0 and with initial velocity 10 (m) to the left. ( So, v(0) = -10(m).)

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter10: Virtual Work And Potential Energy

Section: Chapter Questions

Problem 10.57P: Find the stable equilibrium position of the system described in Prob. 10.56 if m = 2.06 kg.

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