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A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)₂(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 18.55 g PbCl₂ (s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO3)₂(aq) solution.

A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)₂(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 18.55 g PbCl₂ (s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO3)₂(aq) solution.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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McQuarrie Rock Gallogly University Science Books presented by Macmillan Learning A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)₂(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 18.55 g PbCl₂ (s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO₂),(aq) solution. concentration: M Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemistry | Publisher: U 33°F Cloudy
Transcribed Image Text:McQuarrie Rock Gallogly University Science Books presented by Macmillan Learning A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)₂(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 18.55 g PbCl₂ (s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO₂),(aq) solution. concentration: M Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemistry | Publisher: U 33°F Cloudy
Expert Solution
Step 1

The balanced chemical equation for the reaction between NaCl and Pb(NO3)2 is:

Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaNO3(aq)

From the equation, we see that one mole of Pb(NO3)2 reacts with two moles of NaCl to form one mole of PbCl2.

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