A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.Let us first derive the expression for the tension.By Newton's First LawΣF = the components of force that makes this so isΣF = T - = 0Simplifying this results toT = g/(ϕ)Analyzing the figure above, we arrive at(ϕ) = sqrt( 2 + ) / ( / + )By substitution, we arrive at the following:T = ( + 2 ) g / ( sqrt ( 2 + ) )If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal toT = 0.370 N ProblemA solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Findthe tension in the wire.Ldrm Solutiona)Let us first derive the expression for the tension.By Newton's First LawΣF -the components of force that makes this so isΣFΤ= 0Simplifying this results toT =g/(4)Analyzing the figure above, we arrive at(4) = sqrt(+By substitution, we arrive at the following:T =+ 2)g/(sqrt (2+))If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal toT =0.370 N

SOL:- Given :- mass of ball (m) = 45 kg diameter of ball (d) = 32 cm length…

Answered: A solid uniform ball with massm and…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter14: Static Equilibrium, Elasticity, And Fracture

Section: Chapter Questions

Problem 85PQ

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A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.

Let us first derive the expression for the tension.

By Newton's First Law

ΣF =

the components of force that makes this so is

ΣF = T - = 0

Simplifying this results to

T = g/(ϕ)

Analyzing the figure above, we arrive at

(ϕ) = sqrt( ² + ) / ( / + )

By substitution, we arrive at the following:

T = ( + 2 ) g / ( sqrt ( ² + ) )

If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to

T = 0.370 N

Problem
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find
the tension in the wire.
L
d
r
m

Solution
a)
Let us first derive the expression for the tension.
By Newton's First Law
ΣF -
the components of force that makes this so is
ΣFΤ
= 0
Simplifying this results to
T =
g/
(4)
Analyzing the figure above, we arrive at
(4) = sqrt(
+
By substitution, we arrive at the following:
T =
+ 2
)g/(
sqrt (
2
+
))
If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to
T =
0.370 N

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