a) Let us first derive the expression for the tension. By Newton's First Law EF = 0 the components of force that makes this so is EF = T costetha mg = 0 Simplifying this results to T= m g/ cos Analyzing the figure above, we arrive at 2+ cos (0) = sqrt( By substitution, we arrive at the following: T= m + 2 sqrt ( )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N 2.

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Chapter12: Static Equilibrium And Elasticity
Section: Chapter Questions
Problem 59P: A copper wire is 1.0 m long and it diameter is 1.0 mm. if the wire hangs vertically how much weight...
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A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.

Let us first derive the expression for the tension.

By Newton's First Law

ΣF = 

the components of force that makes this so is

ΣF = T -  = 0

Simplifying this results to

T = g/(ϕ)

Analyzing the figure above, we arrive at

(ϕ) = sqrt( 2 +  ) / ( / +  )

By substitution, we arrive at the following:

T =  (  + 2 ) g / (  sqrt ( 2 +  ) )

If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to

T = 0.370 N

Solution
a)
Let us first derive the expression for the tension.
By Newton's First Law
EF = 0
the components of force that makes this so is
IF = T costetha
= 0
mg
Simplifying this results to
T= m
g/ cos
Analyzing the figure above, we arrive at
(4) = sqrt(
+
cos
By substitution, we arrive at the following:
T= m
+ 2
sqrt (
2+
))
If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to
T=
0.370 N
2.
+
Transcribed Image Text:Solution a) Let us first derive the expression for the tension. By Newton's First Law EF = 0 the components of force that makes this so is IF = T costetha = 0 mg Simplifying this results to T= m g/ cos Analyzing the figure above, we arrive at (4) = sqrt( + cos By substitution, we arrive at the following: T= m + 2 sqrt ( 2+ )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T= 0.370 N 2. +
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the
tension in the wire.
L
d
Transcribed Image Text:A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L d
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