Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- A B D Do F 240 N.mm 420 N.mm 300 N.mm 480 N.mm Figure 1 - Torques applied to the driveshaft 1) DERIVE the twist angle expression (mathematical) of the shaft under torque in terms of the geometric properties of the shaft and the applied torque 2) CALCULATE the diameter of the shaft if the twist angle should not exceed 1.5⁰ 3) CALCULATE the maximum shear stress due to torsion. Consider G = 70 GPa. Assume that the length between each segment is 500 mm.arrow_forwardA solid 1.750-in.-diameter steel [G= 13,000 ksi] shaft is subjected to torques TB = 265 lb-ft and TD 90 lb-ft, acting in the directions shown. Assume a = 48 in., b = 72 in., and c = 36 in. If the allowable shear stress in the shaft is 16 ksi, determine the maximum torque Tc that can be applied to the shaft. (1) Answer: Tc i B (2) b Tc (3) Tp lb-ft Darrow_forwardA steel stepped shaft ABCD fixed at A is subjected to three torques at points B, C and D, with magnitudes T₁ = 40 kip-in, T₂ = 50 kip-in and Ts= 30 kip-in and directions as shown in Figure 1.1. The segments AB and BC are solid with diameters dx = 3 in and dec = 2 in respectively, while segment CD is hollow with an outer diameter dan 1.5 in and a wall thickness of 0.25 in. The shear modulus of elasticity is equal to G=11.6x10³ ksl. T₁ T₂ 4 = 20 in A B L₂ = 20 in Figure 1.1 a) Draw the torsion moment diagram for the shaft and calculate how long should segment CD be so that the angle of twist between points B and D is equal to zero. T₁ 4₂-25 in b) If Ts is dropped, a fixed support is added at point D (as shown in Figure 1.2) and the length of segment CD is equal to 15 in, find the support reactions at points A and D and the maximum shear stress developed in segment BC. The magnitudes of the torques at points B and Care the same as in part a). B C L₂= 25 in T₂ * Figure 1.2 Hollow C Hollow…arrow_forward
- Please I want answer of that question from these choicesarrow_forward3) Two circular shafts (shown in Figure) made of the same material and have the same length are subjected to a torque Tequals 150 lb.ft, the angle of twist for the hollow shaft equals that of the solid shaft. A-1/3 C-5.4 B-1 D-3 D=10 in solid shaft D=10 in d=9 in O hollow shaftarrow_forward3. Four pulleys are attached to the 50-mm-diameter aluminum shaft. If torques are applied to the pulleys as shown in the figure, determine the maximum shear stress in each segment and the angle of rotation of pulley D relative to pulley A. Use G = 28 GPa for aluminum. a. Tab= b. Tbc= C. Tbc= ad= 1100 N·m 800 N·m D C 900 N·m 600 N m B A 2 m3 m2 marrow_forward
- I am struggling with this questionarrow_forwardA solid steel shaft of circular cross-section has diameter 50 mm, length 1,028 mm and shear modulus 79.3 GPa. If the allowable shear stress is 36 MPa and the allowable angle of twist is 1.9°, determine the maximum permissible torque. Give your answer in Nm to 1 decimal place.arrow_forwardDetermine the angle of twist of the end A of the A-36 steel shaft shown in Fig.a. Also, what is the angle of twist of A relative to C? The shaft has a diameter of 200 mm.arrow_forward
- The shaft consists of a 3-in diameter aluminum segment that is rigidly joined to a 2-in diameter steel segment. The ends of the shaft are attached to rigid supports, Calculate the angle of twist developed at the interface of the two segments when the torque T = 50 kip٠in is applied. Use G = 4×106 psi for aluminum and G = 12×106 psi for steel.arrow_forwardPlease answer in proper unitsarrow_forwardA compound shaft consists of an outside tube (1) and an inner tub (2) that are fully connected together. Determine the maximun allowable torque that could be applied to the compound shaft if the allowable shear stress in the outer shaft is Tall, 1 = 89 MPa, and the allowable shear stress in the inner shaft is Tall,2 = 62 MPa.[G₁: 39 GPa, G₂ = 16 GPa, d₁ = 102 mm, d₂ = 87 mm, d3 = 55 mm] Tube (1) Tube (2) Answer: d3 d₂ d₁ Tube (1) Tube (2) kN.marrow_forward
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