A soil profile is shown in Figure Q2 (a). Calculate the total stress, pore water pressure and effective stress at points A, B, C and D. Hence, plot the variations of the stresses with depth. Given: H1 = 4.7 m H2 = 6.4 m H3 = 3.8 m e= 0.55 Ysat= 19.1kN/m3 w= 24% Gs = 2.61 e= 0.64

A soil profile is shown in Figure Q2 (a). Calculate the total stress, pore water pressure and effective stress at points A, B, C and D. Hence, plot the variations of the stresses with depth. Given: H1 = 4.7 m H2 = 6.4 m H3 = 3.8 m e= 0.55 Ysat= 19.1kN/m3 w= 24% Gs = 2.61 e= 0.64

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter6: Hydraulic Conductivity

Section: Chapter Questions

Problem 6.8P

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Concept explainers

Principles of Seepage

In hydrology, when water flows down in a pore or crack of unsaturated soil due to gravity, the deep layer of soil is called seepage. It is the slow movement of water in the soil layer. Seepage is mainly found near hydraulic structures and is responsible for the stability of earthen-type hydraulic structures.

Question

A soil profile is shown in Figure Q2 (a). Calculate the total stress, pore water
pressure and effective stress at points A, B, C and D. Hence, plot the variations of the
stresses with depth. Given:

H₁ = 4.7 m H₂ = 6.4 m H₃ = 3.8 m
e= 0.55 Ysat= 19.1kN/m3 w= 24%
Gs = 2.61 e= 0.64

HI =4.7 m
e = 0.55
Gs = 2.61
H2 = 6.4 m
Ysa= 19.1kN/m³
H3 =3.8 m
w = 24%
e = 0.64
Layer I
Groundwater table
H2
- Layer II
Layer III
E Dry sand E Sand E Clay Rock

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