a) Sketch Vo versus time for the circuit shown with the input given. b) Determine DC output voltage without a capacitor. c) If a capacitor of 10 uF is placed in parallel with RL, sketch the vo versus time. d) find the DC output voltage. Given R = R2 = RL = 2.2 k2. %3D

1- In a buck DC/DC converter: ton Va = 100 V, R = 80, D ==0.8, f == 20000 Hz, L = 200 μH, Find: a) average voltage and current of the load Vala. b) maximum and minimum current of inductor. c) Voltage ripple of the capacitor. d) the average input current. e) draw the figure of the inductor current. C1 = 40 Micro farad Q Vd - İd K C1 ww + Vo

R R2 E-

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1) Propose and draw a circuit of a resistive current divider in half

Would you help me with d and c? This is for my practice set. Thank you!

Please answer in typing format solution Sir please help Thanks in advance

A capacitor can be used .............................................. in electrical circuits. Which of the followings fit?   To regulate the currents To regulate the voltages To store energy by deposition of electric charges To provide energy as passive circuit element To store energy in the form of magnetic field To create time varying voltages and currents To dissipate energy To convert elektrik energy into heat or light

1. Enumerate five formulas for series-parallel capacitances across Vt source and draw the circuit. 2. Enumerate five formulas for parallel-series capacitances across Vt source and draw the circuit.

In the diagram below, the switch S has been closed for a long time. A) What is the output voltage Vout? What is the charge on the capacitor? b) The switch is opened, so the output voltage increases. What is the time constant that describes the charging of the capacitor in terms of R and C? c) When Vout reaches 10 V, the switch closes and the capacitor begins to discharge. What is the time constant that describes the discharging in terms of R and C? Hint: Apply Kirchhoff's Rules to both loops and the sum of the currents at the junction above the capacitor in the diagram, and use I=dq/dt. If the switch opens when Vout reaches a lower value, say 5V, the capacitor will charge again, and thus one can cycle the voltage with a time constant determined by the circuit: this demonstrates the principle of operation of an electronic timer. 4R S 15 V Vout R