A sine wave has a maximum value of 440 V. (a) What is its RMS or "effective" value? (b) What is the average value (assume full-wave rectifier)? (c) At what angle of rotation will the voltage reach a value of 120 V?
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- What is the difference between a diode and rectifier?How is a solid-state diode tested? Explain.A sine voltage trace displayed on a screen is shown in figure. The x axis is 1unit=40 ms and y axis is 1 unit=4 v; determine the frequency of the sine wave and plot the waveform if the same is applied to input of a full wave rectifier.
- CIRCUIT DIAGRAM : D1 IÑ4001 AC Source RL 1K Q VOUT PROCEDURES : 1. Construct the half-wave rectifier circuit as shown. 2. Monitor the input voltage using the oscilloscope. Adjust the oscilloscope to show at least two complete cycles of the input signal. Draw the input waveform in Graph 1 and measure the peak-to-peak value. Record this in Table 1. Convert this value into RMS value using the formula: 3. 4. Vp-p Vp-p P-P VRMS 2.828A single-phase half wave uncontrolled rectifier circuit is operating with a purely inductive load and a source voltage of 100 sin (277t) V. An ideal PMMC ammeter is connected in series with the inductive load reads 20 A. Calculate the distortion factor of the rectifier. Answer Choices: a. 0.866 b. 0.707 c. 0.577 d. 0.816A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%
- Zener Diode conducts current in a. reverse direction O b. both reverse and forward O c forward direction Od. Depend of the voltageA single phase – half wave controlled rectifier with freewheeling diode is supplying a load consistingseries connected a resistor and an inductance from a 70.7V (RMS), 50Hz sinusoidal AC source.The firing delay of the thyristor is 90° and the load values are R=10Ω, L=0.1 H. Define the loadcurrent expression and draw the load current by calculating for first two periods. And calculate theaverage values of the load voltage and current.b) A sine voltage trace displayed on a screen is shown in figure5. The x axis is 1unit=50 ms and y axis, 1 unit=2 V; determine the frequency of the sine wave and plot the waveform if the same is applied to the input of a half wave rectifier. V Figure5
- C4 R1 Vout For the precision rectifier circuit shown in Figure C4 what is the correct operation for the circuit if a Sine wave is 10k D1 R2 LM324 VEE applied to the input signal VIN? Vin D2 10k OUT V3 U1A Figure C4 A. When VIn is negative the circuit operates as unity voltage follower providing an in phase sine wave at VouT. When VIN is positive the circuit conducts but only to one diode drop, B. When VIn is negative the circuit operates as an inverting amplifier providing an inverted sine wave at VouT. When VIN is positive the circuit is driven to very close to zero due to amplifier gain reducing the diode drop voltage, c. When VIn is negative the circuit operates as an inverting amplifier providing an in-phase sine wave at VOUT. When VIn is positive the circuit is driven to very close to zero due to amplifier gain reducing the diode drop voltage, D. When VIn is negative the circuit operates as unity voltage follower providing an inverted sine wave at Vour. When VIn is positive the…Question (2) A controlled half-wave rectifier has a 240 V rms 60Hz ac source, The load a is R=30 Ohm resistor (a) Determine the delay angle such that the average load current is 2.5A (b) Determine the power absorbed by the load (c) Determine the power factor.A half wave rectifier, given that, Vs=68sin(2?ft), Ro=10 Ohm, f=50 Hz, What is the value of rectification factor? O a. 81%. O b. 53%. O c. 40%. O d. 76%.