A simple pendulum has a mass of 259 and a force constant of 400dyne/cm. If the ball is shifted to the right by a displacement of 10 cm from its equilibrium position and at a velocity of 40 cm/s. Its frequency: 0.5 Hz 0.63 Hz 0.66 Hz 0.6 Hz
Q: The position of a 0.18 kg oscillating mass is given by x(t) = (4.0 cm) cos(15t) where t is in…
A: Given Mass m = 0.18 kg equation x(t) = (4.0 cm)×Cos(15t)
Q: A ball on a massless, rigid rod oscillates as a simple pendulum with a period of 3.0 s on Earth. If…
A: The period of the pendulum is given as .The gravitational acceleration on the moon is of the value…
Q: The maximum velocity and acceleration of a harmonic oscilator are given as v_max and a max,…
A: The relation between max. acceleration and max. velocity is given as:- amax=kmvmax -----(1)…
Q: If the period of oscillations of a simple pendulum is 4s, the velocity of the bob in the mean…
A: We are given time period of oscillation of simple pendulum. We first find the length of pendulum. We…
Q: ose a diving board with no one on it bounces up and down in a simple harmonic motion with a…
A: Given m1 = 10 kg f1 =4 Hz m2 = 72 kg +10 kg = 82 kg
Q: A 10.2 gram mass is attached to an ideal spring with a spring constant 30 N/m. The mass is displaced…
A: At equilibrium,
Q: A spring with spring constant 15 N/m hangs from the ceiling. A ball is attached to the spring and…
A:
Q: The total energy of a mass/spring system set into simple harmonic motion is 2 J when its amplitude…
A:
Q: The acceleration due to gravity in this problem is taken to be g = 9.80 m/ s2 , unless otherwise…
A: The acceleration due to gravity,
Q: A particle of mass 2.0 kg is attached to a spring of spring constant 30 N/m. If the maximum…
A: mass of the particle, m = 2.0 kg spring constant of the spring, k = 30 N/m maximum acceleration of…
Q: A 5 kg block hangs from a spring with a spring constant of 5 N/m. At t=0s the block is 3 m below…
A:
Q: A pendulum made of a uniform rod with a length of 60.0 cm is set into simple harmonic motion about…
A: The situation is shown in the figure below: When the pendulum is at an small angle θ angle with the…
Q: A 0.5-kg object is connected to a spring that undergoes oscillatory motion. There is friction…
A: The given values are, m=0.5 kgμk=0.06X=0.2 mk=50 N/mFk=0.294 N
Q: A certain pendulum clock that works perfectly on Earth where ag = 9.810 m/s² is taken to the moon,…
A: We know, time period is given as:
Q: A simple pendulum makes 127 complete oscillations in 3.30 min at a location where g = 9.80 m/s2. (a)…
A:
Q: The equation of motion for a mass of 4.0 kg on a horizontal spring (a simple harmonic oscillator) is…
A: Given: m = 4 kg x = 0.5 Cos (3t)
Q: A simple pendulum makes 127 complete oscillations in 3.20 min at a location where g = 9.80 m/s2.…
A: Number of oscillations in 3.20 minutes = 127 using , 1 min = 60 seconds Time taken for 127…
Q: A mass moving back and forth on a spring obeys the sinusoidal equation x(t) = A cos(2πft), where A…
A: Given data: Equation of motion for spring mass system x(t) = A cos(2πft) Amplitude (A) = 10.0 cm…
Q: You are examining a system with a Pendulum, and release it at an angle of 25°. You measure how long…
A: Here given that the pendulum takes 163 sec to complete 50 osciloscillation.It is released at an…
Q: What is the length, in meters, of a simple pendulum if it has a frequency of 4.97 Hz? Assume that…
A: Frequency of simple pendulum (f)= 4.97 Hz Acceleration due to gravity(g)=14.29 m/s^2
Q: A simple pendulum has a length, L = 1m, and a mass of 100 grams. The pendulum is released from angle…
A: Calculate the maximum height to which the pendulum is reached by using the formula h=L-Lcosθ ,…
Q: The period of a simple pendulum is trebled (T' = 3T) when its initial length L is increased by 1.2 m…
A: original length = L new length (L') = L + 1.2original time period = T new time period = T' T' = 3T…
Q: A simple pendulum makes 138 complete oscillations in 2.60 min at a location where g = 9.80 m/s2.…
A: Given data The number of oscillations is given as N = 138. The time taken by one oscillaton is…
Q: A simple pendulum is set into motion at two different times with different initial conditions. The…
A: Here, we use conservation of energy to find out the height reached by the pendulum in both cases.…
Q: A simple pendulum makes 130 complete oscillations in 2.60 min at a location where g = 9.80 m/s2. (a)…
A: Part(a) PERIOD OF PENDULUM? ans. Since pendulum completes 130 oscillation in=2.6 min=156 s so…
Q: The pendulum in a grandfather clock has a period of 1.00 s. If the clock’s driving spring is allowed…
A:
Q: The acceleration due to gravity in this problem is taken to be g = 9.80 m/ s2 , unless otherwise…
A: The time period T (in seconds ) of simple pendulum is given by…
Q: What is the length, in meters, of a simple pendulum if it has a frequency of 3.51 Hz? Assume that…
A: Ferquency (F) = 3.51 Hz Acceleration due to gravity (g) = 11.94 m/s2 let length of the pendulum…
Q: A 50 cm long spring with spring constant 239 N/m has a mass 1.2 kg attached to it, and it can…
A:
Q: What is the frequency, in Hertz, of a simple pendulum if it has a length of 0.6 m? Assume that the…
A: Write the given values with the suitable variables. l=0.6 mg=4.89 m/s2 Here, l is the length and g…
Q: A mass is attached to the end of a spring. It oscillates in simple harmonic motion following: x(t)…
A: A mass is attached to the end of a spring. It oscillates in simple harmonic motion x(t) = (1.0 cm)…
Q: A mass is placed on a frictionless, horizontal table. A spring (k = 100 N/m), which can be stretched…
A: Given, The mass attached to the one end of the spring (m) = 8 kg. Spring constant (k) = 100 N/m. The…
Q: A 0.40-kg mass is attached to a spring with a force constant of k = 387 N/m, and the mass–spring…
A: (a)Given that the mass is 0.40kg, the force constant of the spring is 387N/m, and the amplitude of…
Q: A block attached to a spring, oscillates on a frictionless horizontal surface with a period of 0.3…
A:
Q: When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches…
A: The objective of the question is to find the period of the oscillations when a mass is attached to a…
Q: The period of a simple pendulum is doubled (T' = 2T) when its initial length L is increased by 1.2 m…
A:
Q: As a 0.5-kg mass oscillates on a spring, its maximum potential energy during the oscillation is 4…
A: Vmax = 4m/s
Q: A simple pendulum is set into motion at two different times with difterent initial conditions. The…
A: Apply energy conservation and time period formula.
Q: The bob of a simple pendulum has a speed of 0.2 m/s at its lowest position. Calculate the maximum…
A:
Q: In the physics Lab, you measure a max speed of the pendulum of 0.55m/s. If the maximum deflection…
A: Introduction: Simple pendulum is the construction of weightless string attached to the bob which is…
Q: An object is attached to an ideal spring of spring constant 3.54 N/m. The spring is initially in its…
A: Given: spring constant of spring, k = 3.54 N/m motion of the object is described as y = (6.37 cm)…
Q: What is the frequency
A: 4th option is correct. 1.00 Hz Explanation is in next step.
Q: A mass m at the end of a spring oscillates with a frequency of 0.78 Hz. When an additional 770 g…
A:
Q: A pendulum is formed by placing a horizontal axis at various positions of a measuring stick of…
A: Length of the measuring stick L = 108 cm = 1.08 mGiven that the axis is placed at 81 cm (0.81 m)…
Q: e position with time of an object is given by x(t)=Acos(ωt) If the amplitude is 1.52 m, and the…
A:
Q: A pendulum has a length of 0.15 m and a mass of 2.2 kg. It is pulled from equilibrium at an angle of…
A: Initial angle dors not affect the period of pendulum, So, the formula for period of pendulum will be…
Step by step
Solved in 2 steps
