A set of eight data bytes is stored in memory starting at XX50 H. Write a program to add two bytes at a time and store the sum in the same memory locations, low-order sum replacing the first byte and a carry replacing the second byte. If any pair does not generate a carry, the memory location of the second byte should be cleared.
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- A set of eight data bytes is stored in memory locations starting from XX70H. Write a program to add two bytes at a time and store the sum in the same memory locations, low order sum replacing the first byte and a carry replacing the second byte. If any pair does not generate a carry, the memory location of the second byte should be cleared. Data(H) F9, 38, A7, 56,98,52, 8F, F2Q1- Write a program in assembly language for the 8085 microprocessor to send one byte of data located at the memory address (3000H ) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz . When sending the required byte, you must adhere to the following: The two high bits of the start bits(1 1) must be sent, after that the data bits are sent, after that the low bit of the stop bit (0) is sent. The following flowchart will help you. The solution must be integrated and include the calculation of the baudrate delay timeQ1- Write a program in assembly language for the 8085 microprocessor to send one byte of data located at the memory address (3000H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending the required byte, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you. The solution must be integrated and include the calculation of the baud rate delay time Transmit Set up Character Bit Counter • Send Start Bit No Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes • Add Parity if Necessary Send Two Stop Bits Return (a)
- 3. Implement a 32-bit subtraction of two numbers X and Y that are stored in memory as: X = (DS: 503H) MS byte of MS word (DS: 0502H) (DS: 0501H) (DS: 0500H) LS byte of MS byte of LS byte of MS word LS word LS word Y = (DS:0507H) (DS: 0506H) (DS: 0505H) (DS: 0504H) The result of X - Y is to be saved in the place where X is stored in memory.Implement the Hamming Code error detection and correction algorithm for a group message to be transmitted over a network. Hamming code algorithm allows the receiver to detect errors that may have been introduced due to many factors such as noise, interference, and many others. -> Assume the following: 1. The sender message length is 2 bytes. The data transmitted to the user is the 2-byte data in addition to the parity bits. 2. The receiver must be able to detect and correct 1-bit error. Report :In the report you must include an overview of the Hamming code algorithm and you need to show: 1. The detailed calculation of the minimum number of parity bits needed for a message of 2-byte length. 2. Details on how sender generates the parity bits. 3. Details on how thew receiver detects and corrects a 1-bit error. THANKS., PLEASE GIVE DETAILED DESCRIPTION.Please write the code in MIPS assembly Language Create a MIPS program that corrects bad data using Hamming codes. ECC Hamming codes are explained on pages 420-424 in your text. The program is to request the user to enter a 12-bit Hamming code and determine if it is correct or not. If correct, it is to display a message to that effect. If incorrect, it is to display a message saying it was incorrect and what the correct data is (the 12-bit Hamming code) again in hex. I will be testing only with single bit errors, so the program should be able to correct my tests just fine. You do not need to worry about multiple bit errors. Make certain that you have lots of comments in your code as this is in MIPS. Also make the code neat: line up the command field, the register fields, and the comment fields For this assignment, turn in your code, a screenshot showing a working test case
- code required in mips programming language a .s or .asm code not a c code. Write a MIPS procedure that takes as its two parameters the starting address of a (zero-terminated) string, and a character c, and removes all instances of the character from the string. Also, write a main program to test your procedure. Your main program should input a string from the user (you can assume that the string will be at most 40 characters, not including the zero byte delimiter), and then prompt for input of a character c. If the character c that the user inputs is the newline character (ascii code 10), your program should terminate. Otherwise, your program should invoke your procedure, output the modified string, and then prompt for input of another character to be removed from the string, continuing in this manner until the input character is the newline characterWrite a code in sim8085 for the following problem: The pressure of two boilers is monitored and controlled by a microcomputer works based on microprocessor programming. A set of 6 readings of first boiler, recorded by six pressure sensors, which are stored in the memory location starting from 2050H. A corresponding set of 6 reading from the second boiler is stored at the memory location starting from 2060H. Each reading from the first set is expected to be higher than the corresponding position in the second set of readings. Write an 8085 sequence to check whether the first set of reading is higher than the second one or not. If all the readings of first set is higher than the second set, store 00 in the ‘D’ register. If any one of the readings is lower than the corresponding reading of second set, stop the process and store FF in the register ‘D’. Data (H): First set: 78, 89, 6A, 80, 90, 85 Second Set:71, 78, 65, 89, 56, 752. Consider the two main variables: Number and N. Number is a 1024 byte variable. It represents a huge unsigned integer. N is a 4 byte variable. It represents the number of bits by which the number will be shifted. assenbly language Write an SHL1024 function that receives two parameters on the stack: the address of a number of 1024 bytes and a value giving by how many bits the number of 1024 bytes will be shifted towards the left. This function must act like an SHL but on a 1024 byte variable. On return, the content of the Number variable will be shifted to the left by the number of bits demand. On return, the values of the general registers and the EFLAGS should be the same as before the call to SHL1024
- Convert the above code to three address code do x = x + 2; while (a[x] < t);Assignment for Computer Architecture! this is about hamming codes write the code IN MIPS ASSEMBLY LANGUAGE calculating hamming codes; The key to the Hamming Code is the use of extra parity bits to allow the identification of a single error. Create the code word as follows: Mark all bit positions that are powers of two as parity bits. (positions 1, 2, 4, 8, 16, 32, 64, etc.) All other bit positions are for the data to be encoded. (positions 3, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, etc.) Each parity bit calculates the parity for some of the bits in the code word. The position of the parity bit determines the sequence of bits that it alternately checks and skips.Position 1: check 1 bit, skip 1 bit, check 1 bit, skip 1 bit, etc. (1,3,5,7,9,11,13,15,...)Position 2: check 2 bits, skip 2 bits, check 2 bits, skip 2 bits, etc. (2,3,6,7,10,11,14,15,...)Position 4: check 4 bits, skip 4 bits, check 4 bits, skip 4 bits, etc. (4,5,6,7,12,13,14,15,20,21,22,23,...)Position 8: check 8 bits,…2.- If the binary code for LOAD is (0011), for ADD is (0010), for STORE is (0110), for JMP is (0001) and for END is (0111). Assuming a 16 bits format, write the object code (binary representation) of the following program: Note: use 4 bits for the op-code and 12 bits for the ADDR.