A saturated liquid feed of 500 mol/hr containing 40 mole % water is to be fractionated at 101.325kPa (abs) in order to form a distillate containing 70 mole % water and a bottoms product of 10 mole % water. NOTE: This is actually NOT an ideal solution, e.g. Raoult’s Law does NOT apply. Equilibrium data is available on Blackboard. Assume a distillate reflux ratio (if necessary) of 3:1. a)  Calculate the flowrates (mol/hr) of the distillate and bottoms. b)  Determine the theoretical number of trays and the feed tray number for the specified operation. c)  Determine the minimum reflux ratio, RMIN and the minimum number of theoretical trays at total reflux. d)  Compare the results of (a-c) to the ideal system considered in the previous assignment.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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  1. A saturated liquid feed of 500 mol/hr containing 40 mole % water is to be fractionated at 101.325kPa (abs) in order to form a distillate containing 70 mole % water and a bottoms product of 10 mole % water.

    NOTE: This is actually NOT an ideal solution, e.g. Raoult’s Law does NOT apply.
    Equilibrium data is available on Blackboard. Assume a distillate reflux ratio (if necessary) of 3:1.

    1. a)  Calculate the flowrates (mol/hr) of the distillate and bottoms.

    2. b)  Determine the theoretical number of trays and the feed tray number for the specified operation.

    3. c)  Determine the minimum reflux ratio, RMIN and the minimum number of theoretical trays at total reflux.

    4. d)  Compare the results of (a-c) to the ideal system considered in the previous assignment.

Experimental Data - Water & n-Butanol
T[K]
384.1
380.0
379.6
374.0
369.8
369.5
367.2
366.2
366.2
365.9
365.9
366.0
366.0
368.6
369.0
X
0.000
0.050
0.092
0.097
0.181
0.291
0.303
0.417
0.546
0.550
0.752
0.902
0.980
0.981
0.991
0.992
1.000
y
0.000
0.253
0.388
0.402
0.556
0.660
0.666
0.724
0.750
0.753
0.754
0.754
0.760
0.763
0.839
0.850
1.000
Transcribed Image Text:Experimental Data - Water & n-Butanol T[K] 384.1 380.0 379.6 374.0 369.8 369.5 367.2 366.2 366.2 365.9 365.9 366.0 366.0 368.6 369.0 X 0.000 0.050 0.092 0.097 0.181 0.291 0.303 0.417 0.546 0.550 0.752 0.902 0.980 0.981 0.991 0.992 1.000 y 0.000 0.253 0.388 0.402 0.556 0.660 0.666 0.724 0.750 0.753 0.754 0.754 0.760 0.763 0.839 0.850 1.000
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why can't R min be negative?

 

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Follow-up Question

Thank you so much for all your detailed explanations. I was wondering if you could walk me through how you plotted the VLE graph. I tried using Margules equations to solve for x and y since it is a non-ideal solution but my graph on excel doesn't look like the one you have. Thank you much!

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