A sample of 58 research cotton samples resulted in a sample average percentage elongation of 8.19 and a sample standard deviation of 1.41. Calculate a 95% large-sample CI for the true average percentage elongation u. (Round your answers to three decimal places.) What assumptions are you making about the distribution of percentage elongation? O We assume the distribution of percentage elongation is normal with the value of o known. O We assume the distribution of percentage elongation is uniform. O We assume the distribution of percentage elongation is normal with the value of o unknown. O We make no assumptions about the distribution of percentage elongation.

A normal distribution has a mean of 85.3 and a standard deviation of 4.83. Find the data value corresponding to the value of z given. (Enter your answer to four decimal places.) z = 0.65

Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…

f the standard deviation of a normally distributed population is 22.0 and we take a sample of size 4, then the standard error of the mean is