7-) Solve Only D option with explain D) What is the electric-field magnitude E, in units of V/m, in the rod at x = L/2? (!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.A rod of semiconducting material of length L = 4 m and cross-sectional area A = 3.5 mm2 lies along the x-axisL. The material obeys Ohm's law, and its resistivity varies along the rod according to0 and x =x21between x =p = Powhere po = 3 × 10-4 2 · m. The end of the rod at x =O is at a potential Vo15 V greater thanL²the end at x =L.A) What is the total resistance, in units of 2, of the rod?

Name: 7-) Solve Only D option with explain D) What is the electric-field mag
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: 7-) Solve Only D option with explain D) What is the electric-field magnitude E, in units of V/m, in the rod at x = L/2? (!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.A rod of semiconducting material of length L = 4 m and cross-s

The given values are, L=4 mA=3.5 mm2ρ=ρ01-x2L2ρ0=3×10-3 Ω·mVo=15 V

Science

Physics

A rod of semiconducting material of length L = 4 m and cross-sectional area A = 3.5 mm2 lies along the x-axis between x = 0 and x = L. The material obeys Ohm's law, and its resistivity varies along the rod according to (1-) p = Po where po = 3 × 10¬ª N · m. The end of the rod at x = 0 is at a potential Vo = 15 V greater than L² the end at x = L.

A rod of semiconducting material of length L = 4 m and cross-sectional area A = 3.5 mm2 lies along the x-axis between x = 0 and x = L. The material obeys Ohm's law, and its resistivity varies along the rod according to (1-) p = Po where po = 3 × 10¬ª N · m. The end of the rod at x = 0 is at a potential Vo = 15 V greater than L² the end at x = L.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter28: Current And Resistance

Section: Chapter Questions

Problem 69PQ

See similar textbooks

Similar questions

What current flows through a 2.54-cm-diameter rod of Pure silicon that is 20.0 cm long, when 1.00103 V is applied to it? (Such a rod may be used to make nuclear- particle detectors, for example.)
(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 5 m and cross-sectional area A = 2.5 mm? lies along the x-axis between z = 0 and a = L. The material obeys Ohm's law, and its resistivity varies along the rod according to ρ ρυ where on = 1.5 x 10 40.m. The end of the rod at z == 0 is at a potential Vo = 20 V greater than the end at z= L. A) What is the total resistance, in units of N, of the rod? Answer: B) What is the current, in units of miliamperes in the rod? Answer: C) What is the electric potential, in units of Volt, in the rod at x = L/2? Answer: D) What is the electric-field magnitude E, in units of V/m, in the rod at z = L/2? Answer:
A rod of semiconducting material of length L 2 m and cross-sectional area A- 4.5 mm? lies along the x-axis between z0 and a- L The material obeys Ohm's law, and its resistivity varies along the rod according to p= p(1 where po4x 10 n m. The end of the rod at z=0 is at a potential V- 15 V greater than the end at z-L L2 A) What is the total resistance, in units of fn, of the rod?
(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L the x-axis between a = 7 m and cross-sectional area A = 2.5 mm2 lies along L. The material obeys Ohm's law, and its resistivity varies along the %3D 0 and z = (1) rod according top= Po where po = 2.5 x 10N. m. The end of the rod at a = 0 is at a L2 %3D potential Vo = 40 V greater than the end at z = L. A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer: C) What is the electric potential, in units of Volt, in the rod at z = L/2? Answer:
A rod of semiconducting material of lenght L=3 m and cross-sectional area A=4.5 mm^2 lies along the x-axis between x=0 and x=L. The material obeys ohm's law, and resistivity varies along the rod according to p=p0 (1-(x^2/L^2)) where p0= 4.10^-4 ohm.m. The end of the rod x=0 is at a potential V0=30V greater than the x=L. A) what is the total resistance, in units of ohm, of the rod? B) what is the current, in units of miliamperes, in the rod? C) what is the electric potential, in units of Volt, in the rod at x=L/2? D) what is the electic-field magnitude E, in units of V/m, in the rod at x=L/2?
A copper wire is 10 cm long and has a cross-sectional area of 0.4 mm^2 and the resistance of the wire is 0.4 ohms. The wire is connected to a source with a voltage of 10 v, what is the movement, knowing that the density of conduction electrons for copper is 8.5 x 10^28 m^-3 8.5 x 10^4 63-5 For the same wire in the previous question, what is the fersi level if the atomic weight of copper is 0.5 x 10^(-5) 0.94 x 10^(-4) 7.03| ev 0.36 x 10^(-4) 7.01eV 7.05 eV 7.021 ev
(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 4m and cross-sectional area A = 4 mm? lies along the x-axis between a = 0 and a = L. The material obeys Ohm's law, and its resistivity (1=) varies along the rod according to p = Po where po = 4 × 10 4 2. m. The end of the rod at r = 0 is at a potential Vo = 35 V greater than the end at x = L. L² A) What is the total resistance, in units of N, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer: C) What is the electric potential, in units of Volt, in the rod at a = L/2? Answer: D) What is the electric-field magnitude E, in units of V/m, in the rod at a = L/2? Answer:
Chapter 26, Problem 051 GO Wire C and wire D are made from different materials and have length Lc = LD = 1.4 m. The resistivity and diameter of wire C are 5.4 x 10-6 2-m and 1.28 mm, and those of wire D are 3.9 x 10-6 Q:m and 0.53 mm. The wires are joined as shown in the figure and a current of 4.6 A is set up in them. What is the electric potential difference between (a) points 1 and 2 and (b) points 2 and 3? What is the rate at which energy is dissipated between (c) points 1 and 2 and (d) points 2 and 3? -Lp (a) Number Units (b) Number Units (c) Number Units (d) Number Units
(a) A 35.5-m length of copper wire at 20.0°C has a radius of 0.31 mm. If a potential difference of 8.00 V is applied across the length of the wire, determine the current in the wire. (Use the values in the following table.) Material Resistivity" (N :m) Temperature Coefficient of Resistivityb a [(°C)-'] a Silver 1.59 x 10-8 3.8 × 10-3 Copper 1.7 x 10-8 3.9 x 10-3 Gold 2.44 x 10-8 3.4 x 10-3 Aluminum -8- 2.82 x 10 3.9 x 10 Tungsten 5.6 x 10-8 4.5 x 10-3 Iron 10.0 x 10-8 5.0 x 10-3 Platinum 11 x 10-8 3.92 x 10-3 Lead 22 x 10-8 3.9 x 10-3 Nichrome 1.00 x 10-6 0.4 x 10-3 Carbon 3.5 x 10-5 -0.5 x 10-3 Germanium 0.46 -48 x 10-3 Silicond 2.3 x 103 -3 -75 x 10 Glass 1010-1014 Hard rubber *1013 Sulfur 1015 Quartz (fused) 75 x 1016 (a) All values at 20°C. All elements in this table are assumed to be free of impurities. (b) See the section "Resistance and Temperature". (c) A nickel-chromium alloy commonly used in heating elements. The resistivity of Nichrome varies with composition and ranges…
We have a copper conductor, length l = 1m and circular section of diameter d = 4mm a) Calculate the resistance of the conductor between its ends. b) If a current of 1 amp flows through said conductor: I) Calculate the drag speed of the electrons. II) calculate the number of electrons per second that cross the conductor section. Data: resistivity of copper PCu = 1.7 × 10-8 -8 ampere m: numerical density of charge carriers [nCu] = 8.5 × 1028 atoms m-3: resistivity of aluminum p Al = 2.8 × 10-8 ampere m elemental load = 1.6x10-19 C
Pure copper has a resistivity of 1.68 x 10-8 Nm. Some accurate cubes of copper are prepared, and electrical measurements are made, for which current is passed across a pair of opposite faces. a) Comparing a 2.5 cm cube and a 5 cm cube, which will have the higher conductance? Ex- plain your answer. b) Given eight 1 cm cubes, how can they be stacked to get the highest and the lowest resis- tance between opposite faces of the stack? Calculate the resistance of each stack.
4) Gold wire Al = 10 m long cylindrical wire made of gold (resis- tivity pAu = 2.44 × 10¬8 Nm at To = 20° C, temperature coefficient aAu = 3.4 x 10-3 (°C)¯) has a resistance of R = 12. a: What is the radius r of the wire? b: If the wire is twice as long, the radius is ... 1. twice as big O 2. 2 larger O 3. a fourth O c: What is the resistance of the wire at T 1000° C? %3D