A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm² lies along L. The material obeys Ohm's law, and its resistivity varies along the rod where po = 5 x 10 4N · m. The end of the rod at z = 0 is at a potential the x-axis between z = 0 and æ = according to p = po (1 L² Vo = 30 V greater than the end at a = L. D) What is the electric-field magnitude E, in units of V /m, in the rod at z = L/2? Answer:

A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm² lies along L. The material obeys Ohm's law, and its resistivity varies along the rod where po = 5 x 10 4N · m. The end of the rod at z = 0 is at a potential the x-axis between z = 0 and æ = according to p = po (1 L² Vo = 30 V greater than the end at a = L. D) What is the electric-field magnitude E, in units of V /m, in the rod at z = L/2? Answer:

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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