A rigid shallow foundation 1 × 2 m is shown in the scheme. Calculate the elastic settlement at the centre of the foundation. q= 150 kPa 1m E, (kPa) 1m. 1 10000 Sand Hs=0.3 2 8000 3 4 12000 Rock Scheme 3.2 1m g=150 kPa z, m Sand Hs =0.3 0-2.5 7 2.5-6.5 11 6.5– 10.0 14 Scheme 3.3 Assume the rock layer exists at depth z = 10 m. (u) z

Principles of Foundation Engineering (MindTap Course List)
9th Edition
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Author:Braja M. Das, Nagaratnam Sivakugan
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Chapter6: Shallow Foundations: Ultimate Bearing Capacity
Section: Chapter Questions
Problem 6.21P: Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5...
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Ignoring the given Es-data and considering that the supporting soil is clean, normally consolidated sand with the following available data:

A rigid shallow foundation 1 × 2 m is shown in the scheme. Calculate the elastic settlement at the centre of the
foundation.
q= 150 kPa
1m
E, (kPa)
1m.
1
10000
Sand
Hs=0.3
2
8000
3
4
12000
Rock
Scheme 3.2
1m
g=150 kPa
z, m
Sand
Hs =0.3
0-2.5
7
2.5-6.5
11
6.5– 10.0
14
Scheme 3.3
Assume the rock layer exists at depth z = 10 m.
(u) z
Transcribed Image Text:A rigid shallow foundation 1 × 2 m is shown in the scheme. Calculate the elastic settlement at the centre of the foundation. q= 150 kPa 1m E, (kPa) 1m. 1 10000 Sand Hs=0.3 2 8000 3 4 12000 Rock Scheme 3.2 1m g=150 kPa z, m Sand Hs =0.3 0-2.5 7 2.5-6.5 11 6.5– 10.0 14 Scheme 3.3 Assume the rock layer exists at depth z = 10 m. (u) z
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