A researcher claims that the proportion of students who have traveled abroad is greater than 45%. To test this claim, arandom sample of 750 students is taken and its determined that 374 students have traveled abroad.The following is the setup for this hypothesis test:Ho : p-0.45Ha :p>0.45In this example, the p-value was determined to be 0.004come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%)Select the correct answer below:The decision is to reject the Null Hypothesis.The conclusion is that there is enough evidence to support the claimThe decision is to fail to reject the Null Hypothesis.The conclusion is that there is not enough evidence to support the claim

A hypothesis test is carried out to check the claim proportion of students travelled abroad is…

Answered: A researcher claims that the proportion…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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e. Consider the following hypothesis test. H: 4, - H, = 0 H.:H,- H, #0 The following results are for two independent samples taken from the two populations. Sample 1 n, = 70 x; =106 o, = 8.4 a. What is the value of the test statistic? Sample 2 n, = 80 x, =108 0z = 7.6 b. What is the p-value? c. With a=0.01 , using the p-value approach, what is your hypothesis testing conclusion? Why? Explain.
When we test the hypothesis that the population proportions are equal, we can use the Z test for a one-sided as well as a two-sided alternative. Select one: a. False b. True C. Not sure
A researcher is interested in assessing if there are differences in the average number of monthly religious event attendances across religious affiliations. Religious event attendance is measured as an interval-ratio variable: it is the number of events that each survey respondent reported attending in the previous month. Religious affiliation is measured as a nominal variable with the following categories: Protestant, Catholic, Jewish, Muslim, Hindu, Buddhist, other, and not religious. Which of the following hypothesis tests would be appropriate, given the types of variables presented? O Chi-square test O Two-sample difference-of-proportions z-test O ANOVA O One-sample difference-of-proportions z-test
A publisher reports that 56 % of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 200 found that 47 % of the readers owned a particular make of car. State the null and alternative hypotheses. Answer 囲 Tables E Keypad Keyboard Shortcuts Ho:
Suppose are running a study/poll about the proportion of women over 40 who regularly have mammograms. You randomly sample 118 people and find that 98 of them match the condition you are testing.Suppose you have the following null and alternative hypotheses for a test you are running:H0:p=0.8H0:p=0.8Ha:p>0.8Ha:p>0.8Calculate the test statistic, rounded to 3 decimal places
In 1942, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?" Of the 1100 adults surveyed, 440 indicated that they were total abstainers. In a recent survey, the same question was asked of 1100 adults and 418 indicated that they were total abstainers. Complete parts (a) and (b) below. C "1.M1 M2 Find the test statistic for this hypothesis test. 0.96 (Round to two decimal places as needed.) Determine the P-value for this hypothesis test. (Round to three decimal places as needed.)
A null and alternative hypothesis are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. Ho: p = 0.3 Ha: p 0.3. What type of test is being conducted in this problem? OA. Two-tailed test OB. Left-tailed test OC. Right-tailed test Save
A college administrator claims that the proportion of students that are nursing majors is greater than 40%. To test this claim, a group of 400 students are randomly selected and its determined that 190 are nursing majors. The following is the setup for this hypothesis test: Ho : p=0.40 Ha: p > 0.40 Find the test statistic for this hypothesis test for a proportion. Round your answer to 2 decimal places. Provide your answer below: TestStatistic
Test the claim that the proportion of men who own cats is significantly different than 50% at the 0.02 significance level.a.) The null and alternative hypothesis would be: b.) The test is: right-tailed left-tailed two-tailed Based on a sample of 60 men, 59% owned cats c.) The sample proportion ˆp=d.) The test statistic is: (to 2 decimals)e.) At α=α=0.02, the critical value is:± (to 2 decimals)f.) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
A law enforcement agent believes that 80% of the drivers stopped on Saturday nights for speeding are under the influence of alcohol. Suspecting that the proportion under the influence may be higher than 80%, a SRS of 140 drivers who were stopped for speeding on a Saturday night was taken. 119 of the drivers in the sample were under the influence of alcohol. The correct set of hypotheses is Group of answer choices Ho: p = 0.80 vs Ha: p = 0.85 Ho: p = 0.80 vs Ha: p > 0.80
‏......... is a theory based on insufficient evidence that requires further testing to prove whether the observed data false . Select one : a . Hypothesis b . All the above points c . Variables d . Null Hypothesis
A two-sample z-test for two population proportions is to be performed using the P-value approach. The null hypothesis is Hn: P, = p, and the altemative is H: P, #p2. Use the given sample data to find the P-value for the hypothesis test. Give an Interpretation of the p-value. A state university found it lost 25 students out of 352 in 2013 and 36 students out of 334 in 2014. O A P-value = 0. 0455; There is about a 4.55% chance that the two proportions are equal. O B. P-value = 0.091; If there is no difference in the proportions, there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation. OC. P-value = 0.0455; there is no difference in the proportions, there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. O D. P-value = 0. 091; There is about a 9.1% chance that the two proportions are equal. O E. P-value = 0.9545: there is no difference in the proportions, there is about a 95.45% chance of…

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