A research center survey of 2,374 adults found that 1,926 had bought something online. Of these online shoppers, 1,208 are weekly online shoppers. Complete parts (a) through (c) below. a. Construct a 95% confidence interval estimate of the population proportion of adults who had bought something online. (Round to four decimal places as needed.)

In a survey of 3116 adults aged 57 through 85​ years, it was found that 86.2​% of them used at least one prescription medication. Complete parts​ (a) through​ (c) below. a. How many of the 3116 subjects used at least one prescription​ medication? b. Construct a​ 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. c. What do the results tell us about the proportion of college students who use at least one prescription​ medication?     A. The results tell us that there is a​ 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part​ (b).   B. The results tell us​ that, with​ 90% confidence, the probability that a college student uses at least one prescription medication is in the interval found in part​ (b).   C. The results tell us​ that, with​ 90% confidence, the true proportion of college students who use at…

In a survey of 3213 adults aged 57 through 85​ years, it was found that 83.9​% of them used at least one prescription medication. Complete parts​ (a) through​ (c) below. a. how many of the 3213 subjects used at least one prescription medication?  b. construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. c. what do the results tell us about the proportion of college students who use at least one prescription medication?

According to recent data by the American Marketing​ Association, 76.5​%of people in the​ 18-24 age group used social media in 2017. You want to find out what the social media proportion is among your classmates who are all between 18 and 24 years old. Suppose you obtain a random sample of 229 students and find that 202 students in this sample are active social media users. Complete parts a through c below.   a. Construct a 99​% confidence interval to estimate the actual proportion of social media users. A 99​% confidence interval to estimate the actual proportion has a lower limit of------ and an upper limit of------- ​(Round to three decimal places as​ needed.) b. What is the margin of error for this​ sample? c. Is there evidence that this proportion matches that of the overall population based on the​ sample?

In a survey of 2300 adults, 718 say they believe in UFOS. Construct a 90% confidence interval for the population proportion of adults who believe in UFOS. A 90% confidence interval for the population proportion is (,). (Round to three decimal places as needed.)

Answer Part B

Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1004 and x = 575 who said "yes." Use a 90% confidence level. E Click the icon to view a table of z scores. .... a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.)

A researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 480 college students showed that 23​% of them​ had, or intended​ to, cheat on examinations. Find the​ 95% confidence interval for the population proportion. Round to four decimal places.

A survey of 41 students in grades 4 through 12 found 63% have classroom Wi-Fi access. Find the 99% confidence interval of the population proportion. .

The owner of the west end Kwick fill gas station wishes to determine the proportion of customers who pay at the pump using credit card or debit card. He surveys 100 customers and finds that 85 pay at the pump. (Round your answers to 3 decimal places.)  a. Estimate the value of the population proportion:  b. Develop a 95% confidence interval for the population proportion.