MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Homa An education researcher claims that 60% of college students work year-round. In a random sample of 300 college students, 180 say they work year-round. Al a=0.05, is there enough evidence to reject the researcher's claim? Complete parts (a) through (e) below. O C. Atleast % of college students work year-round. book OD. The percentage of college students who work year-round is not %. cer Contents Let p be the population proportion of successes, where a success is a college student who works year-round. State Ho and H. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) O A. Ho p# GB. H, p=0.60 media Library OC. Ho P Plan OF. Ho ps H, p Tor Success (b) Find the critical value(s) and identify the rejection region(s). sible Resources Identify the critical value(s) for this test. for Success %3D (Round to two decimal places as needed. Use a comma to separate answers as needed.) Clear all Check answer View an…arrow_forwardResearchers wondered if there was a difference between males and females in regard to some common annoyances. They asked a random sample of males and females, the following question: "Are you annoyed by people who repeatedly check their mobile phones while having an in-person conversation?" Among the 505 males surveyed, 171 responded "Yes"; among the 522 females surveyed, 202 responded "Yes." Does the evidence suggest a higher proportion of females are annoyed by this behavior? Complete parts (a) through (g) below. C -0.0484 ő 0 0.0484 (e) Determine the P-value based on the model from part (d). First find the test statistic for this hypothesis test. (Round to two decimal places as needed.)arrow_forwardMany fundraisers ask for donations using email and text messages. A paper describes an experiment to investigate whether the proportion of people who make a donation when asked for a donation by email is different from the proportion of people who make a donation when asked for a donation in a text message. In this experiment, 1.7% of those who received and opened an email request for a donation and 7.8% of those who received a text message asking for a donation actually made a donation. Assume that the people who received these requests were randomly assigned to one of the two groups (email or text message) and suppose that the given percentages are based on sample sizes of 2,000 (the actual sample sizes in the experiment were much larger). (Let p1 be the proportion who make a donation after receiving an email, and p2 be the proportion who make a donation after receiving a text message.) Find the test statistic and P-value. (Use a table or SALT. Round your test statistic to two…arrow_forward
- A research group conducted an extensive survey of 2940 wage and salaried workers on issues ranging from relationships with their bosses to household chores. The data were gathered through hour-long telephone interviews with a nationally representative sample. In response to the question, "What does success mean to you?" 1470 responded, "Personal satisfaction from doing a good job." Let p be the population proportion of all wage and salaried workers who would respond the same way to the stated question. How large a sample is needed if we wish to be 95% confident that the sample percentage of those equating success with personal satisfaction is within 1.6% of the population percentage? (Hint: Use p ≈ 0.50 as a preliminary estimate. Round your answer up to the nearest whole number.) workersarrow_forwardIn a survey of 1000 adult Americans, 45.7% indicated that they were somewhat interested or very interested in having web access in their cars. Suppose that the marketing manager of a car manufacturer claims that the 45.7% is based only on a sample and that 45.7% is close to half, so there is no reason to believe that the proportion of all adult Americans who want car web access is less than 0.50. Is the marketing manager correct in his claim? Provide statistical evidence to support your answer. For purposes of this exercise, assume that the sample can be considered as representative of adult Americans. Test the relevant hypotheses using ? = 0.05. Find the test statistic and P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z= P-value= chose the conclusion in the context of the problem. a) Reject H0. We do not have convincing evidence that the proportion of all adult Americans who want car web access is less than 0.5. The marketing…arrow_forwardA recent survey of 1030 U.S. adults selected at random showed that 627 consider the occupation of firefighter to have very great prestige. Estimate the probability (to the nearest hundredth) that a U.S. adult selected at random thinks the occupation of firefighter has very great prestige.arrow_forward
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- ??arrow_forwardBased on information from Harper's Index, 37 out of a random sample of 100 adult Americans who did not attend college believe in extraterrestrials. However, out of a random sample of 100 adult Americans who did attend college, 47 claim that they believe in extraterrestrials. Does this indicate that the proportion of people who attend college and who believe in extraterrestrials is higher than the proportion who did not attend college? (a) State the hypotheses in plain language. (b) Fill in the table below, then enter this table in the left side of the Rossman-Chance applet. No college College Total Believe in ETs 84 Did not believe in ETs 116 Total 100 100 200 (c) Compute the point estimate for the difference in the proportion believing in extraterrestrials between those not attending college and those attending college. Pne – Pe = (d) Complete at least 1000 simulations in the Rossman-Chance app 2 and report your findings below. (For help with the applet, refer to the e "Using the…arrow_forwardSleep apnea is a condition in which the sufferers stop breathing momentarily while they are asleep. This condition results in lack of sleep and extreme fatigue during waking hours. A current estimate is that 16.3 million out of the 312.7 million Americans suffer from sleep apnea, or approximately 5.2%. A safety commission is concerned about the percentage of commercial truck drivers who suffer from sleep apnea. They do not have any reason to believe that it would be higher or lower than the population’s percentage. To test the claim that the percentage of commercial truck drivers who suffer from sleep apnea is not 5.2%, a simple random sample of 380380 commercial truck drivers is examined by a medical expert, who concludes that 29 suffer from sleep apnea. Does this evidence support the claim that the percentage of commercial truck drivers who suffer from sleep apnea is not 5.2%? Use a 0.01 level of significance. Step 1 of 3 : State the null and alternative hypotheses for the test.…arrow_forward
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