A research group conducted an extensive survey of 3052 wage and salaried workers on issues
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- Cyberbullying In 2018, the Pew Research Center did a study on cyberbullying. A sample of 743 teens were asked if they had ever experienced any of the below 6 types of cyberbullying while online or via their cellphone. Those who selected yes to one or more of these questions were considered to be a target of cyberbullying. (Source: Pew Research Center, September 2018, "A Majority of Teens Have Experienced Some Form of Cyberbullying") Offensive name-calling Spreading of false rumors Receiving explicit images they didn't ask for Constant asking of where they are, what they're doing, who they're with, by someone other than a parent Physical threats Having explicit images of them shared without their consent a.) A total of 438 of the sampled teens were considered a target of cyberbullying. Find a 92% confidence level for the proportion of all teens in the U.S. who are a target of cyberbullying. (Round answers to three decimal places.)margin of error: lower limit: upper limit:arrow_forwardA study was performed to examine the personal goals of children in grades 4, 5, and 6. A random sample of students was selected from each of grades 4, 5, and 6 from schools in Georgia. The students received a questionnaire regarding achieving personal goals. They were asked what they would most like to do at school: make good grades, be good at sports, or be popular. The results are presented in the table below, grouped by the sex of the child. Top Personal Goal Boys Girls Make good grades 96 295 Be popular 32 45 Be good in sports 94 40 Reference: Ref 14-9 The numerical value of the χ2 statistic for this table isarrow_forwardA contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 57 people she sampled who work out in the morning have a mean of 4.8 hours of exercise each week. The 56 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.3 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2: Construct a 95 % confidence interval for the true difference between the mean amounts of time…arrow_forward
- Male and female respondents to a questionnaire about gender differences are categorized into three groups. Group 1 Men Women 40 6 Group 2 48 54 Group 3 80 34arrow_forwardA J.D. Power and Associates vehicle quality survey asked new owners a variety of questions about their recently purchased automobile One question asked for the owner's rating of the vehicle using categorical responses of average, outstanding, and exceptional. Anothe question asked for the owner's education level with the categorical responses some high school, high school graduate, some college, and college graduate. Assume the sample data below are for 500 owners who had recently purchased an automobile. Education Quality Rating Average Outstanding Exceptional Some HS HS Grad Some College College Grad 35 30 25 65 50 50 50 95 15 20 25 40 a. Use a 0.05 level of significance and a test of independence to determine if a new owner's vehicle quality rating is independent of th owner's education. Compute the value of the test statistic (to 2 decimals). 6.57 Use Table 3 of Appendix B to find the p-value. The p-value is greater than 0.10 What is your conclusion? Cannot conclude that the…arrow_forwardplease answer a, b, carrow_forward
- he Computer Anxiety Rating Scale (CARS) measures an individual’s level of computer anxiety, on a scale from 20 (no anxiety) to 100 (highest level of anxiety). Researchers at Miami University administered CARS to 172 business students. One of the objectives of the study was to determine whether there are differences in the amount of computer anxiety experienced by students with different majors. They found the following: Major n Mean Marketing 19 44.37 Management 11 43.18 Other 14 42.21 Finance 45 41.80 Accountancy 36 37.56 MIS 47 32.21 (A) Complte the following ANOVA table: Source of Variation SS df MS F-ratio F-crit Between groups 3172 5 634.4 4.9567 2.2685 Within groups 21246 166 127.988 Total 24418 171 (A) At the 0.05 level of significance, is there evidence of a difference in the mean computer anxiety…arrow_forwardA consumer group wanted to determine if there was a difference in customer perceptions about prices for a specific type of toy depending on where the toy was purchased. In the local area there are three main retailers: W-Mart, Tag, and URToy. For each retailer, the consumer group randomly selected 5 customers, and asked them to rate how expensive they thought the toy was on a 1-to-10 scale (1= not expensive, to 10 = very expensive). The toy was priced the same at all retail stores. Compute the percentage of variance explained by the group differences for these data. Q: Percentage and variance explained = ?arrow_forwardNational Guard. The U.S. Department of Defense collects data on active members in the National Guard. Results are published in Selected Manpower Statistics. According to that document, 77.0% of members are in the Army National Guard and 10.2% of members are Black and in the Army National Guard. What percentage of members in the Army National Guard are Black?arrow_forward
- In a study researching how donating to charity can affect a person's happiness, 96 participants were given $5 a day for one week. Each participant was randomly assigned to one of two groups. Those assigned to the first group were asked to spend the money on themselves, and those assigned to the second group were asked to donate the money to charity. At the end of the week, all of the participants were asked to rate their overall level of happiness on a scale from 0 to 100, with higher scores indicating greater levels of happiness. Which of the following are the appropriate null and alternative hypotheses to test whether the sample data provide convincing statistical evidence that donating to charity results in greater happiness than spending on oneself, on average? Ho self- "charity = 0 (A) Ha self charity >0 Ho self Mcharity=0 (B) Ha self charity 0 (E) Ha self = Mcharity <0arrow_forwardA survey by the National Institutes of Health asked a random sample of young adults (aged 19 to 25 years), "Where do you live now? That is, where do you stay most often?" Here is the full two-way table (omitting a few who refused to answer and one who reported being homeless): Survey Type Female Male Total Parents' home 923 986 1909 Another person's home 144 132 276 Living location Own place 1294 1129 2423 Group quarters 127 119 246 Total 2488 2366 4854 Should we use a chi-square test for homogeneity or a chi-square test for independence in this setting? Justify your answer. Chi-square test for homogeneity. The data came from a single random sample (n = 4854 young adults aged 19 to 25 vears), with the individuals classified according to two categorical variables (gender and "Where do you live now?"). O Chi-square test for homogeneity. The data came from two independent random samples (n=2488 young adult females and n = 2366 young adult males aged 19 to 25 years), with the individuals…arrow_forwarda. P(Democrat|same) = b. P(Democrat and same) =arrow_forward
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