A rectangular loop of width w and height h is set in the plane of the page so that one side is a distances from a long cable. The long cable carries a current I. [Hint: Type "pi" for and "mu_0" for μo-] (a) Write an expression for the magnetic flux through the loop in terms of I, w, h, and s. + = mu_0lw/(2pi)In((h+s)/s) The current in the wire decreases according to the equation I = Ae-kt. The rectangular loop has a resistance R. Answer the following in terms of A, k, R, w, h, and s. (b) Write an expression for the current induced in the loop as a function of time. Iloop = W (c) What is the total energy dissipated in the loop from t = 0 to t = infinity? E =

A loop of wire in the shape of a rectangle of width w and length L and a long, straight wire carrying a current I lie on a tabletop as shown in the figure below. A long, straight, horizontal wire carries current I toward the right. A rectangular loop of wire, with length L and height w, lies below the straight wire. The length is parallel to the straight wire, and the top edge of the loop is a distance h below the straight wire. (a) Determine the magnetic flux through the loop due to the current I. (Use any variable stated above along with the following as necessary: ?0.) ΦB =          (b) Suppose the current is changing with time according to I = a + bt, where a and b are constants. Determine the magnitude of the emf (in V) that is induced in the loop if b = 20.0 A/s, h = 1.00 cm, w = 20.0 cm, and L = 1.25 m.  How do you determine the induced emf from your equation for the flux from part (a)? V (c) What is the direction of the induced current in the rectangle?…

How to solve this question

Consider the seven current-carrying wires and the four closed paths shown in the figure. For each of these paths (C1, C2, C3, and C4) determine the following in terms of ?0. Use standard sign convention for the currents; minus is down into the page and positive is up out of the page. (Assume I1 = 2.00 A, I2 = 2.00 A, I3 = 5.00 A, I4 = 6.00 A, I5 = 5.00 A, I6 = 6.00 A, and I7 = 7.00 A.)