MATLAB: An Introduction with Applications
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Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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A random sample of 7,000 had a proportion of interest of 0.535. Is there sufficient evidence, at the 5% level of significance, to support the hypothesis that the true population proportion is not 0.521? State your conclusion in the form of a sentence including both the test statistic and the critical value.
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- The US Department of Energy reported that 48% of homes were heated by natural gas. A random sample of 331 homes in Oregon found that 132 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 1% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) H0: H1: Based on the hypotheses, compute the following:Test Statistic = p-value = Based on the above we choose to The correct summary would be: that the proportion of homes in Oregon that were heated by natural gas is different than what the DOE reported value of 48%.arrow_forwardAccording to the most recent General Social Survey, 70% of adults watch TV nightly. A researcher believes that the proportion of college students who watch TV nightly is less than this. To test this claim the research samples 400 college students and finds that 276 watch TV nightly. At the 0.05 level of significance does this data provide evidence to suggest that the proportion of college students who watch TV nightly is less than 70%? Select the correct hypothesis test for this problem:arrow_forwardSuppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…arrow_forward
- Use the information below, gathered from 1000 students from a small college who disclosed their age as well as their preference for type of instruction, to determine whether or not there is an association between age and preferred type of instruction. Write your hypotheses, perform the test, find the test statistic, the p-value, and state your conclusion. Assume a significance level of � = 0.01. AGE 18 & under 19-25 26-35 36-45 65 or Older online 43 56 26 20 20 Scheduled Zoom 48 75 34 26 20 Hybrid Zoom 82 19 88 83 59 Face to Face 27 50 52 71 101 a) Write your hypotheses.b) Use your calculator to determine the test statistic and p-value.c) Using the significance level provided, write an appropriate conclusionarrow_forwardWhat is the population of interest? And what are the hypotheses?arrow_forwardIn a survey, 32% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too high, so she randomly selected 230 pet owners and discovered that 66 of them spoke to their pet on the telephone. Does the veterinarian have a right to be skeptical? Use the α=0.1 level of significance. Find test statistic and p valuearrow_forward
- According to a report on consumer fraud and identity theft, 20% of all complaints for a year were for identity theft. In that year, Rhode Island had 717 complaints of identity theft out of 3498 consumer complaints. Does this data provide enough evidence to show that Rhode Island had a higher proportion of identity theft than 20%? Test at the 5% level. State the hypotheses. Họ: p ? Ha: P Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .05, reject Ho. O Since the p-value is greater than .05, fail to reject Hg. O Since the p-value is less than .05, fail to reject Hg. O Since the p-value is greater than .05, reject Ho. Interpret the results. O At the 5% level of significance, there is enough evidence to show that the proportion of complaints due to identity theft in Rhode Island is more than…arrow_forwardThe US Department of Energy reported that 48% of homes were heated by natural gas. A random sample of 317 homes in Oregon found that 166 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 5% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: P Test Statistic = 0° p-value = H₁: p Based on the hypotheses, compute the following: #v oº 48 48 <-Need answer, please. <-Need answer, please OB 0° Based on the above we choose to Fail to reject the null hypothesis ✓ OB The correct summary would be: There is not enough evidence to support the claim that the proportion of homes in Oregon that were heated by natural gas is different than what the DOE reported value of 48%.arrow_forwardSuppose a researcher wants to estimate the population proportion of defective light bulbs. He took a random sample of 800 light bulbs and 40 of them found out to be defective. Suppose the researcher claims that the defective proportion of light bulb is less than 7%. Suppose he wants to test this claim at 5% significance level. Calculate the test statistics. (Round your answer to two decimal places )arrow_forward
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