The US Department of Energy reported that 49% of homes were heated by natural gas. A random sample of 327 homes in Oregon found that 143 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 10% significance level. Give answer to at least 4 decimal places. a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) H0:                   H1:                     Based on the hypotheses, compute the following:b. Test Statistic = c. p-value =  d. Based on the above we choose to       e. The correct summary would be:       that the proportion of homes in Oregon that were heated by natural gas is different than what the DOE reported value of 49%. Question HelpQuestion 14:   Video1

A survey was conducted that asked 1013 people how many books they had read in the past year. Results indicated that x=10.3 books and s=16.6books. Construct a 90​% confidence interval for the mean number of books people read. Interpret the interval.   Construct a 90​% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. ​(Use ascending order. Round to two decimal places as​ needed.)   A. There is a 90​% probability that the true mean number of books read is between ___ and ____   B. There is 90​% confidence that the population mean number of books read is between ___ and ____.   C. If repeated samples are​ taken, 90​% of them will have a sample mean between ___ and ___.

When a researcher changes their data analyses to get the p-value they desire, that is known as  a. HARKing b. p-hacking c. multiple comparisons d. a Type II error

Random samples of students at 107 four-year colleges were interviewed several times since 1998. Of the students who reported drinking alcohol, the percentage who reported bingeing at least three times within the past two weeks was 41.1% of 336 students in 1998 and 21.6% of 843 students in 2004. a. Estimate the difference between the proportions in 2004 and 1998, and interpret. b. Find the standard error for this difference. Interpret it. c. Define the two relevant population parameters to compare in the context of this exercise. d. Construct and interpret a 90% confidence interval to estimate the true difference. e. State the assumptions for the confidence interval in part d to be valid. ... A. The number of students in the population in 2004 who reported drinking alcohol that binged at least three times within the past two weeks. B. The proportion of the student population in 1998 who reported drinking alcohol that binged at least three times within the past two weeks. C. The number…

Several studies showed that after eating a low-fat cereal for two meals a day​, subjects had lost some weight.A cereal companyfinanced this research. Identify what is wrong. Choose the correct answer below.     A. Since the research is composed of voluntary response​ samples, there may be key data points missing.   B. The data used in the studies is not reliable because it was not measured by the administrator.   C. It is questionable that the sponsor is a cereal company because this sponsor can be greatly affected by the conclusion.   D. It is not possible to take accurate measurements.

A statistician changes her level of significance from .001 to .05.  What impact will this change have on her risk of making a Type I and Type II error?  Is the change in the level of significance a good decision?  Why or why not?

A survey was conducted that asked 963 people how many books they had read in the past year. Results indicated that x=14.7 books and s=17.8  books. Construct a 90​% confidence interval for the mean number of books people read. Interpret the interval.Construct a 90​% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice.​(Use ascending order. Round to two decimal places as​ needed.)A. If repeated samples are​ taken, 90​% of them will have a sample mean between ___ and ____                                B. There is a 90​% probability that the true mean number of books read is between ____ and ___                             C. There is a 90​% confidence that the population mean number of books read is between ___ and ___