A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.74 hours, with a standard deviation of 2.41 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.37 hours, with a standard deviation of 1.92 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (41 - 42)- Let u, represent the mean leisure hours of adults with no children under the age of 18 and µz represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for (H -H2) is the range from hours to hours. (Round to two decimal places as needed.

A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.74 hours, with a standard deviation of 2.41 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.37 hours, with a standard deviation of 1.92 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (41 - 42)- Let u, represent the mean leisure hours of adults with no children under the age of 18 and µz represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for (H -H2) is the range from hours to hours. (Round to two decimal places as needed.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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