MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.1 and a standard deviation of 16.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <µarrow_forwardA sample of 30 randomly selected patients in a waiting room at a doctor’s office reported a mean wait time of 38.5 minutes. If the population standard deviation is 1.78 minutes, find a 95% confidence interval for the population mean wait time.arrow_forwardIn a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.5 and a standard deviation of 19.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? O mg/dL < µarrow_forwardA random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.17 hours, with a standard deviation of 2.45 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.44 hours, with a standard deviation of 1.71 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u1-2) Let u, represent the mean leisure hours of adults with no children under the age of 18 and u, represent the mean leisure hours of adults with children under the age of 18. The 95% confidence interval for (H, -µ2) is the range from hours to hours. (Round to two decimal places as needed.)arrow_forwardA random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.88 hours, with a standard deviation of 2.49 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.29 hours, with a standard deviation of 1.76 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u, - H2). Let u, represent the mean leisure hours of adults with no children under the age of 18 and µ, represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for (µ1 - H2) is the range from hours to hours. (Round to two decimal places as needed.)arrow_forwardIn a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.6 and a standard deviation of 17.5. 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The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenarrow_forwardIn a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.7 and a standard deviation of 18.2. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. 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