A random sample of 16 pharmacy customers showed the waiting times below (in minutes).3201618111521221924The 90% confidence interval19231620Click here for the Excel Data FileFind a 90 percent confidence interval for μ, assuming that the sample is from a normal population. (Round your standard deviationanswer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.)Answer is complete but not entirely correct.21.762 to26.2382017

From the provided information,n = 16Confidence level = 90%

Answered: A random sample of 16 pharmacy…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of 36 students are drawn from the NUST student population, and their body weights are measured. Their results show a mean weight of 84 kg with a standard deviation of 14.8 kg. When constructing a confidence interval estimate for the single unknown population mean weight for the NUST student population, What will be the lower limit (LL) for this confidence interval estimate? a. 75.55 b. 80.40 c. 90.45 d. None of the provided Due to the sharp increase in the prices of urban properties over the last five years, only a small percentage of new city dwellers can afford to buy their own property. According to a recent survey, only 22% of these new city dwellers can afford to buy their own property. An estate agency who wanted to verify this, considered a random sample of 200 recent city dwellers, and found that only 38 of them bought their property in town. Test at the 5% significance level whether the percentage has changed. State the alternative hypothesis a. Ha :…
A random sample of 16 pharmacy customers showered the waiting times below (in minutes) 17 18 16 20 20 12 19 19 15 27 14 23 15 25 18 20 Find the 90% confidence interval for y (but backward), assuming that the sample is from a normal population. (Round your standard deviation answer to 4 decimal places and t-value to 3 decimal places. Round answers to 3 decimal places) The 90% confidence interval ______ to _______.
A simple random sample of size n=24 is drawn from a population that is normal distributed. The sample mean is found to be x bar= 66 and the sample standard deviation is found to be s= 16.construct a 98% confidence interval about the population mean. (Round to two decimals)
An researcher found that a random sample of 30 used cars in a town had a mean gas mileage (mpg) of 19.5 miles per gallon with a sample standard deviation of 3.9 miles per gallon. Assume the population of miles per gallon (mpg) values is normally distributed. Calculate the margin of error, E, for a 95% confidence interval for µ, the average miles per gallon of all used cars in the town. A. 1.78 B. 1.40 C. 1.46 D. 1.44
A scientific paper reported the following summary information on fracture toughnesses (MPa) of n = 169 ceramic bars fired in a particular kiln: = 89.10, s = 3.73.a) Calculate a confidence interval (bilateral) for the average true fracture toughness using a 95% confidence level. Could it be said that the average true fracture toughness was accurately estimated?b) Assume that the investigators believed a priori that the population standard deviation was approximately 4 MPa. Based on this assumption, how large a sample would have to be to estimate μ to within 0.5 MPa with 95% confidence for each side? Note:The exercise in the image is in Spanish, to make the exercise more understandable.
What price do farmers get for their seedless watermelon crops? In a recent month, a simple random sample of 31 farming regions gave a sample mean of $12.15 per 100 pounds of seedless watermelon. Assumer that σ=$1.46 per 100 pounds. Find the sample size necessary for a 90% confidence level with a margin of error E=0.61 for the mean price per 100 pounds of seedless watermelon. (Increase to the next whole number.)

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