A random sample of 100 employees at a company shows that 42 drive US made automobiles (the rest drive imported cars even though some are made in the USA). Form a 90% confidence interval for the proportion of all employees who drive US made cars. The interval is 0.42 ± what margin of error?

A random sample of 100 employees at a company shows that 42 drive US made automobiles (the rest drive imported cars even though some are made in the USA). Form a 90% confidence interval for the proportion of all employees who drive US made cars. The interval is 0.42 ± what margin of error?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: In a sample of 300 adults, 228 had children. Construct a 90% confidence interval for the true…

A: Given C=90% Confidence level X=228 N=300

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

Q: In a sample of 310 adults, 205 had children. Construct a 99% confidence interval for the true…

A: Given data, n=310 x=205 p=x/n=205/310=0.661 z-value at 99% confidence is Zc=2.576

Q: A Dean of a certain business school is interested in the difference in proportions of A's given by…

A: Givenn1=800x1=240n2=800x2=160p1^=x1n1=240800=0.3p2^=x2n2=160800=0.2α=1-0.95=0.05α2=0.025zα2=1.96

Q: Out of 100 people sampled, 77 had kids. Based on this, construct a 95% confidence interval for the…

A: We have to find 95% confidence interval for the true population proportion of people with kids.

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage. Find the 99%…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…

A: The sample size, i.e., the sampled number of adults, n=350.The sampled number of adults with…

Q: Out of 400 people sampled, 344 had kids. Based on this, construct a 99% confidence interval for the…

A: Given that sample size n = 400 Number of peoples with kids, X = 344 The critical value of Z at 99%…

Q: A sample of 200 found that 43.2% of those sampled consumed more than 2 alcoholic beverages a week.…

A: Given:

Q: Out of 400 people sampled, 232 had kids. Based on this, construct a 95% confidence interval for the…

Q: In a sample of 270 adults, 151 had children. Construct a 90% confidence interval for the true…

A: Given that Sample size n =270 Favorable cases x =151 Sample proportion p^=x/n =151/270 =0.5593

Q: In the 2021-22 season, Klay Thompson made 114 out of 296 three point shots. Create a 95% confidence…

A: Solution: Given information: n= 296 Sample size x= 114 successes p^=xn=114296=0.3851 Sample…

Q: A recent survey showed that among 850 randomly selected subjects who completed 4 years of college,…

A: I'm providing the solution below please do refer it and let me know if you have any queries…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: The Centers for Disease Control and Prevention reported a survey of randomly selected Americans age…

A: Confidence interval for Proportions : The following is the formula for confidence interval of the…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents’ homes. A random…

A: Given X1=986, n1=2253, X2=923, n2=2629

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120 significance level =…

Q: In a sample of 500 adults, 340 had children. Construct a 99% confidence interval for the true…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of a population…

Q: In a sample of 110 adults, 76 had children. Construct a 95% confidence interval for the true…

A: It is given that, in a sample of 110 adults, 76 had children. It is needed to find a 95% confidence…

Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…

A: 0.604 < p < 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…

Q: people from Tanjung Malim has been given cholesterol tests, and 60 of these people had levels over…

A: We have given that, Favorable cases (X) = 60 and sample size (n) = 150 Then, We will find the 95%…

Q: A report statesb that 44% of home owners had a vegetable garden. how large a sample is needed to…

A: Answer: Using the given data, A report stated that 44% of home owners had a vegetable garden, P =…

Q: In a sample of 240 adults, 180 had children. Construct a 95% confidence interval for the true…

Q: In a random sample of 500 Americans, 25% indicated that they have a cat for a pet. Estimate with 97%…

Q: In a sample of 360 adults, 245 had children. Construct a 99% confidence interval for the true…

Q: In a sample of 290 adults, 261 had children. Construct a 95% confidence interval for the true…

A: Given : Sample Size, n = 290 Number of successes, x = 261

Q: Joe’s Pizza Joint found that 64.2% of the 328 pizzas sold last week included pepperoni. Find a98%…

A: Obtain the 95% confidence interval for the proportion of Joe’s customers that order pepperoni. The…

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…

A: Sample size, Number of adults having children, Confidence level is .

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

Q: A sample of 400 homeowners includes 124 that expect their home to increase in value in the next…

A: Margin of error: ME=Zα/2 * √p̂(1-p̂)/n

Q: A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…

A: Given A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

Q: statistics class took a random sample of students at the school to find the proportion of those who…

A: Given that Sample sizes n1=75 , n2=45 Favorable cases x1=12 , x2=9

Q: 9. A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence…

A: In a survey of 280 homeless persons showed that 63 were veterans.

Q: In a sample of 400 adults, 220 had children. Construct a 90% confidence interval for population…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

A random sample of 100 employees at a company shows that 42 drive US made
automobiles (the rest drive imported cars even though some are made in the
USA). Form a 90% confidence interval for the proportion of all employees who
drive US made cars. The interval is 0.42 + what margin of error?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Out of 500 people sampled, 330 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four places
A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random sample by the National Institutes of Health included 2253 men and 2629 women in this age group. The survey found that 986 of the men and 923 of the women lived with their parents. Construct and interpret a 99% confidence interval for the difference in the true proportions of men and women aged 19 to 25 who live in their parents' homes. What conditions are met? (select all that apply) (Remember you check BOTH populations.) O 923 > 30 O 10(923) 30 O 2253 > 30 O a random sample V 2629 > 30 O 986 > 10 O 10(2629) 10 O 1706 > 10 O 923 > 10 O 10(986) < all men aged 19 to 25 O 10(2253) < all men aged 19 to 25 O O
Out of 400 people sampled, 220 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to four places
A student found that in a random sample of 300 people in a town, 105 play sports. Based on this sample, construct a 90% confidence interval for the population proportion of all people in the town who play sports.Give your answers as decimals, rounded to three decimal places.
A research poll of 1501 adults showed that 1051 of respondents believe in global warming. Find a 98% confidence interval estimate for the proportion of adults that believe in global warming. Based on these results, can we safely conclude that the majority of adults believe in global warming and why?
Of 102 randomly selected adults, 42 were found to have high blood pressure. A 90% confidence interval for the true percentage of all adults that have high blood pressure is . What is the value of ? (Round to two decimal places).
In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places
Out of 400 people sampled, 76 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to three places
A survey of 80 recent arcanum students showed that 46 were ready for summer break. Find the 95% confidence interval of the true proportion of students ready for summer break.
In a sample of 470 adults, 306 had children. Construct a 99% confidence interval for the true population proportion of adults with children.Give your answers as decimals, to three places < p <
In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <
A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a 95% confidence interval for the proportion of adults who have a Facebook page.