A quarterback is standing on the football field preparing to throw a pass. His receiver is standing 24 yd down the field and 14 yd to the quarterback's left. The quarterback throws the ball at a velocity of 63 mph toward the receiver at an upward angle of 40°. Write the initial velocity vector of the ball, 7, in component form. = 40° 24 yd 14 yd (Round your answer to 1 decimal place)

The force vector F has a magnitude of F = 385 lb and acts at point A at an angle 0 = 7.7° with respect to vertical as shown. The force F is balanced by the tension forces parallel to the two rods AC O is satisfied. Determine the tension forces and AB such that the vector equation F + F AC + F AB = in the two rods in Cartesian components. a B, A Cc O O BY NC SA 2013 Michael Swanbom NF Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 ft b 2.3 ft 3.8 ft For the component notation, use an 'xy' coordinate system with 'y' poining up and 'x' pointing to the right. F AC = j) lb + F AB = j) lb

The hamstrings pull on the tibia with a force of 510 N at 30 degrees to the bone: that is the angle between the force vector and tibia is 30 degrees. The distance along the tibia from the knee joint center to the tendon insertion is 3.5 cm. What is the magnitude of the force component that is parallel to the tibia?

Two vectors have the following magnitude, A = 9.6 m and B = 6.8 m. Their vector product is:  A⨯B = -3.7 m i + 8.6 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |A⨯B| = AB sin(θ) Note: Bold face letters represents a vector.

i know we have to use cross product and dot product but how do we determine the "two" possible values for these vectors? dont we just take the smallest of the two?   please explain how we get two possible values of scalar product.

What is the direction of the vector product A × B? Use the legend in the box to indicate direction. a В (out) (out) O (in) zero in C b zero a e h out

Scalars and vectors:  Vector A has a magnitude of 9.0 and Vector B has a magnitude of 3.0. If the vectors are at an angle of 30.0º, what is the magnitude of the cross product A x B?                                                      Here are the choices:     13.5   16.2   23.4   27.0

QUESTION -Find the angle between the two vectors: 101 + 5ĵ – 3k and B = 5î + 2j + k A = %3D Note: Report the angle in whole number. No need to write the degrees in the answer box for this item. Present your solution in detailed. It will be submitted after the exam. Next »

What are the magnitude and direction of the cross product rAB×F, where rAB is the position vector and F is the force vector, respectively?

Problem 3.