calculate the cosine of the angle between this two vectors : A=3i+j+k B=-2i-3j-k

given A = 3i-4k and B = 2i-j-k  How do I find the angle subtended by (A-B) and (A cross B)

12.0 B = 5.0 F = 20.0 86400 365) %3D 24 (6)60) = Esc 60° A = 10.0 30 30° 53° D = 20.0 37° Assuming the +x-axis is horizontal to the right for the vectors in the figure, find the following scalar products. a. Ā . B- b. Č - (- 3) - c. Dx F- a. (5 x F) - ( x Ã) -

Two vectors have the following magnitude, A = 8.7 m and B = 10.6 m. Their vector product is: A:B = -2.7 m i+ 8.6 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |A:B| = AB sin(0) Note: Bold face letters represents a vector.

Find a unit vector perpendicular to A = (î+ ĵ – Îk) and B = ( 2i + j- 3k). (Hints. One method to find the unit vector C perpendicular to A and B will be to use the fact that the cross product is perpendicular to both vectors A and B, but keep in mind that the magnitude of the unit vector is one. There is another method which is a little bit longer by using the fact that the dot product AC=0 and BC=0 where C is the unit vector )

For the vectors shown in the figure, find the magnitude and direction of the vector product A C. B' 6. 70° 40° 8. 48, directed out of the page 45. directed out of the page O 16. directed out of the page O 48, directed into the page O 45, directed into the page ) 16, directed into the page

For the vectors in the figure, with a = 8.0, b = 6.0, and c = 10  what are the magnitude and the direction b×c?

If the two displacement vectors with magnitudes of 6.0 m and 8m which could not be a possible choice  12.8 10.0 14.8 2.3 6.6

Find the angle between the vectors a = <1,2,-3> and b = <-2,1,1> in degrees