
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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A quantity of electricity equal to 6.95 × 104 C passes through an electrolytic cell that contains a solution of Sn4+(aq) ions. Compute the maximum chemical amount, in moles, of Sn(s) that can be deposited at the cathode.
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- 4. Write the overall balanced equation for the spontaneous process occurring in the following cell. (Hint: this is the combination of two half-reactions. One is a reduction half-reaction, and the other is an oxidation half-reaction.) Then, calculate the standard potential, E°, for the cell. Zn (s) | Zn *2 (aq) || Cu +2 (aq) | Cu (s)arrow_forwardFind the voltage of the cell if the right half-cell contains 0.330 M AgNO₃ (aq) and the left half-cell contains 0.115 M Cu(NO₃)₂ (aq). Express your answer to three significant figures.arrow_forward4. For the following redox reaction in a galvanic cell, write the oxidation half-reaction and the reduction-half reaction, and calculate the standard cell potential of the reaction. Use Table 1 from the background as needed. Explain how you identified which substance was oxidized and which was reduced. Show all of your work. Redox reaction: Cu(s) + 2 Fe* (aq) → Cu?+ (aq) + 2 Fe* (aq) Table 1. Standard reduction potentials. Half-Reaction E°(Volts) F,(g) + 2e → 2F (aq) CI, (g) + 2e → 2CI(aq) Br, () + 2e → 2Br(aq) Ag*(aq) + e¯ → Ag(s) +2.87 +1.36 +1.07 +0.80 Fe*(aq) + e → Fe²"(aq) +0.77 Cu²*(aq) + 2e' → Cu(s) +0.34 2H*(aq) + 2e¯ → H,(g) 0.00 Fe2*(aq) + 2e' → Fe(s) -0.44 Zn*(aq) + 2e' → Zn(s) -0.76 Al³*(aq) + 3e' → Al(s) -1.66 Mg"(aq) + 2e' → Mg(s) -2.37 Ca²"(aq) + 2e" → Ca(s) -2.87 K*(aq) + e' → K(s) -2.93 В U T T O Word(s)arrow_forward
- Consider the following balanced equation for a redox reaction in an electrochemical cell: 3 Cd (s) + 2 NO3 (aq) + 8 H* (aq) → 3 Cd²+ (aq) + 2 NO(g) + 4H2O (1I) E°cell = 1.36 V Calculate the value of pH of the solution containing H*(aq) when the nonstandard cell potential (Ecell) is measured to be 1.12 V given the following conditions at 25 °C: [NO3] = 0.15 M; [Cd²+] = 0.46 M; PNO = 0.28 bar %3D %3Darrow_forwardWrite the balanced chemical equation for the spontaneous redox reaction. Include states of matter. Calculate the standard cell potential. If the initial concentrations of Zn2+ and of OH– are 1.0 × 10–7 and 2.0 × 10–7, respectively, calculate the cell potential after the Zn2+ concentration has increased by a factor of 100. At this point, what percentage of the initial voltage remains?arrow_forwardWhat is the cell reaction for the following voltaic cell? AI(s) | AI³*(aq) || Br"(aq) | Br2(g) | Pt(s) O A(s) + Al3* (aq) → Br (aq) + Br2(g) O AI(s) + 2 Br (aq) → Br2(g) + A13+(aq) O 2 AI(s) + 3 Br2(g) → 2 Al3+ (aq) + 6 Br (aq) O 2 A13* (aq) + 6 Br¯(aq) → 2 AI(s) + 3 Br2(g) O Al(s) + 3 Br2(g) → Al3+(s) + 2 Br (aq)arrow_forward
- What is the overall reaction for the following cell line notation of a galvanic cell? Al(s)|AI3*(aq) || H*(aq) |H2(g)|Pt(s) 2H2(g) + Al3+*(aq) + Pt(s) → Al(s) + PtH4(s Al(s) + 3H*(aq) + Pt(s) → AI3+(aq) + PtH3(s) 3H2(g) + 2AI3*(aq) → 6H*(aq) + 2AI(s) 2AI(s) + 6H*(aq) → 2AI3+(aq) + 3H2(g 2A13+(aq) + 6H*(aq) → 3H2(g) + 2Al(s)arrow_forward4. For the following redox reaction in a galvanic cell, write the oxidation half-reaction and the reduction-half reaction, and calculate the standard cell potential of the reaction. Use Table 1 from the background as needed. Explain how you identified which substance was oxidized and which was reduced. Show all of your work. Redox reaction: Cu(s) + 2 Fe" (aq) → Cu?+ (aq) + 2 Fe?+ (aq) Table 1. Standard reduction potentials. Half-Reaction E°(Volts) F,(g) + 2e → 2F(aq) CI, (g) + 2e → 2CI(aq) +2.87 +1.36 Br, () + 2e → 2Br(aq) +1.07 Ag*(aq) + e¯ → Ag(s) +0.80 Fe3*(aq) + e' → Fe2*(aq) +0.77 Cu²"(aq) + 2e' → Cu(s) +0.34 2H*(aq) + 2e¨ → H,(g) 0.00 Fe2*(aq) + 2e' → Fe(s) -0.44 Zn"(aq) + 2e' → Zn(s) -0.76 Al³*(aq) + 3e' → Al(s) -1.66 Mg2 (aq) + 2e → Mg(s) -2.37 Caа" (аg) + 2е > Ca(s) -2.87 K*(aq) + e' → K(s) -2.93 B O Word(s)arrow_forwardHelp with the following questionarrow_forward
- Metallic magnesium can be made by the electrolysis of molten MgCl2.(a) What mass of Mg is formed by passing a current of 8.75 A through molten MgCl2 for 2.80 days? The unbalanced chemical reaction representing this electrolysis is shown below.MgCl2 Mg + Cl2 ____g of Mg is formed by this electrolysis.(b) How many minutes are needed to plate out 17.00 g of Mg from molten MgCl2 using 5.2 A current? _____minutes are needed.arrow_forwardIdentify the CORRECT cell notation for the galvanic cell (diagram below) that involves an acid-catalysed redox reaction (spectator ions are not included). V Anode Cathode Pt(s) Cu(s) +H CI Cu²+ CIO, 3 ª. Pt(s) | CIO3¯(aq), Cl¯(aq), H*(aq) || Cu(s) | Cu²+ (aq) Ob. ´Cu(s) | Cu²+ (aq) || CIO3¯(aq), Cï¯(aq), H*(aq) | Pt(s) C. 2+ Pt(s) | CIO3¯(aq), CI¯(aq) || Cu(s) | Cu²+ (aq) O d. Cu(s) | Cu²+( ²+(aq) || CIO3¯¯(aq), Cl¯¯(aq) | Pt(s) e. ´Cu(s) | Cu²+ (aq) || CIO3¯(aq), Cï¯(aq), H*(aq)arrow_forwardPb(s) Determine which of the following statements about the cell shown are True or False. True The standard cell potential, o, equals 0.93 V. True As the reaction proceeds, the concentration of the silver ions decreases. False Cations move to the lead half-cell. True The mass of the silver electrode is increasing. True The silver half-cell is the cathode. False The cell, as represented by the line notation, is a voltaic cell. True True The lead electrode is the anode. Electrons are spontaneously produced in the silver half-cell. salt bridge Ag(s) Pb+2 So Pb2+2e → Pb(s) AS NO3 E--0.13V Ag + le → Ag(s) E° - +0.80V Pb(s) Pb2+ (1M) || Ag+ (1M) | Ag(s)arrow_forward
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