A proton moving at 4.00 × 106 m/s through a magnetic field of magnitude 1.70 T experiences a magnetic force of magnitude of 8.20 × 10−13 N. What is the angle between the proton’s velocity and the field? Hint: Use the equation F = qvB sin θ to get the value of the angle, θ. Show solution

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Chapter1: Units, Trigonometry. And Vectors
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A proton moving at 4.00 × 106 m/s through a magnetic field of magnitude 1.70 T
experiences a magnetic force of magnitude of 8.20 × 10−13 N. What is the angle
between the proton’s velocity and the field?

Hint: Use the equation F = qvB sin θ to get the value of the angle, θ.
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