College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Q3. A proton has a mass of 1.67 x 10-27 kg, has a charge of 1.60 x 10-19 C, and moves is a circle of radius 21.0 cm perpendicular to a magnetic field of 4000G. Find (a) the speed of the proton and (b) the period of the motion.
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- In a mass spectrometer, a beam of protons enters a magnetic field. Some protons make exactly a one-quarter circular arc of radius 0.50 m. a) If the field is always perpendicular to the proton's velocity, what is the field's magnitude if exiting protons have a kinetic energy of 10. keV? b) How long does it take the proton to complete the quarter circle? c) Find the net force (magnitude) on a proton while it is in the field.arrow_forwardCalculate the magnetic force on an electron in the following cases. Provide your answers in component form (Here i, j, k denote the unit vectors for the x,y, and z directions, respectively.): a. A proton with velocity v = (1.20×104 i) m/s moving in a magnetic field of magnitude (0.7 k) T. Fx Fy F₂ Submit Answer Tries 0/10 = b. A proton with velocity v = (1.70×104 i) m/s moving in a magnetic field of magnitude (0.05 i + 0.7 j) T. Fx = Fy= F₂= Submit Answer Tries 0/10 c. A proton with velocity v = (1.50×104 i +5.00×10³ j) m/s moving in a magnetic field of magnitude (0.65 i + 0.85 k) T. Fx Fy= F₂ = Submit Answer Tries 0/10 Fy b. A proton with velocity v = (2.70×104 i +2.10×104 j+ 1.40×104 k) m/s moving in a magnetic field of magnitude (0.95 i -0.75 j + 0.2 k) T. Fx = = F₂ = Submit Answer Tries 0/10arrow_forwardAn electron moves up at a velocity of 9.8 x 104 m/s and has a magnetic force of 5.6 x 10-18 N pointed to the right. (me = 9.11 x 10-31 kg) a) What is the direction of the magnetic field? b) What is the strength of the magnetic field? c) What is the radius of the circle the electron makes?arrow_forward
- An electron moves with velocity v= (7.0i−6.0j)×10^4 m/s in a magnetic field B = (−0.80i+0.60j)T . a. Determine the x -component of the force on the electron. b. Determine the y -component of the force on the electron. c. Determine the z -component of the force on the electron.arrow_forwardA proton is moving in a region where the magnetic and electric fields are perpendicular to each other and produce no net force. If the electric field has a strength of 5.00 x 10^6 N/C and the magnetic field has a strength of 0.800 T, how fast was the proton moving in m/s? a. 4.00 x 10^6 m/s b.6.25x10^6 m/s c.2.5x10^-7 m/s d.1.6x10^-7 m/sarrow_forwardPart 2) A proton moving with a speed 3.84 × 10° m/s through a 2.99 T magnetic field experiences a force of magnitude 1.59 x 10-12 N. (Mass of the proton = 1.673 × 10¬27 kg, charge 1.602 × 10-19 C). What is the angle between the proton's velocity and the magnetic field? Part 3) What is the proton's acceleration? a = m/s?arrow_forward
- When a proton has a velocity of (2i+8j)*10^6 m/s , it experiences a force of -1.6*10^-13k N. . In a second experiment with the same B field, the particle is moving along the + z-axis and under these new conditions it experiences a force along the + x-axis . What is the magnetic field? answer should be in (i,j,k)arrow_forwardIn 1897, the English physicist J. J. Thomson used crossed electric and magnetic fields to measure the charge to mass ratio of electrons. (A) Determine the ratio in SI units. (B) Determine the charge to mass ratio of a proton. (C) In one experiment, electrons are accelerated to speed v by an electric field E, and are then deflected by a magnetic field B. For the parameters given below, calculate the radius of the circular arc in the magnetic field. electric field = = 2.85 kV/cm; distance of the acceleration = 0.84 m; magnetic field = 0.08 T ]arrow_forward
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