A projectile of mass m moves to the right with a speed v; (see figure below). The projectile strikes and sticks to the end of a stationary rod of mass M, length d, pivoted about a frictionless axle perpendicular to the page through O. We wish to find the fractional change of kinetic energy in the system due to the collision. The moment of inertia of a rod is I = moment of inertia of a particle is I = mr². Md² and the 12 a. What is w, the angular speed of the system after the collision. Answer: W= mdvi Md²+md² b. What is the kinetic energy before the collision? Answer: KE₁ = m(v₁) ². c. What is the kinetic energy after the collision? m²d² Answer: KEy = 2 ( M² +4 m²) (v₁) ² 1/ 12

A projectile of mass m moves to the right with a speed v; (see figure below). The projectile strikes and sticks to the end of a stationary rod of mass M, length d, pivoted about a frictionless axle perpendicular to the page through O. We wish to find the fractional change of kinetic energy in the system due to the collision. The moment of inertia of a rod is I = moment of inertia of a particle is I = mr². Md² and the 12 a. What is w, the angular speed of the system after the collision. Answer: W= mdvi Md²+md² b. What is the kinetic energy before the collision? Answer: KE₁ = m(v₁) ². c. What is the kinetic energy after the collision? m²d² Answer: KEy = 2 ( M² +4 m²) (v₁) ² 1/ 12

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A projectile of mass m moves to the right with a speed vi (see figure below). The projectile strikes and sticks to the end of a stationary rod of mass M, length d, pivoted about a frictionless axle perpendicular to the page through O. We wish to find the fractional change of kinetic energy in the system due to the collision. The moment of inertia of a rod is I = Md² and the moment of inertia of a particle is I = mr². 12 a. What is w, the angular speed of the system after the collision. mdvi Md²+1md² 12 b. What is the kinetic energy before the collision? Answer: KE¡ = m(v¡)². c. What is the kinetic energy after the collision? (0₁)² Answer: W= 1 m²d² Answer: KE₁ = = =+M₁2² +² md² 12 4 m O d M O 3
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