A physics student constantly swings a slinky side to side, with an amplitude of 20 cm. This motion generates a standing wave. How could that standing wave be described? antinodes = 40 cm, nodes = 0 cm, wavelength = 1.75    antinodes = 20 cm, nodes = 0 cm, wavelength = 1.5 λ   antinodes = 20 cm, nodes = 0 cm, wavelength = 1.75 λ   antinodes = 40 cm, nodes = 0 cm, wavelength = 1.5

We used an experimental setup like the one shown below. The length of the string between the string vibrator and the pulley is L = 2.00 m. The mass per unit length or linear density of the string is μ = 0.0005 kg/m. The string vibrator can oscillate at any frequency. The hanging mass is 511 g. Frictionless pulley String vibrator μl= dm dx The wavelength of the fifth mode (n = 5) is m. The frequency of the fifth mode (n = 5) is Hz. The tension in the string is close to When the mode of vibration is increased to n = 10, the wave speed of the string will → 2 The wave speed on the string is m/s. N. constant Drag answer here Drag answer here Drag answer here Drag answer here Drag answer here m Hanging mass 500 125 remain the same 0.8 100 2.0 increase

A wave has a wavelength of 30 cm. What is the phase difference between two points on this wave that are 45 cm apart? π/4 rad π/3 rad π/2 rad 2π/3 rad π rad

A 1m long string is pinned at both ends. The string is plucked, and a standing wave is created. The wave number is ? = 4? rad/m.a) Calculate the wavelength of the wave.b) If there are 5 nodes in the string, find their positions.Answers: • 0.5 m• Xn = {0, 0.25, 0.5, 0.75, 1}