A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal support. The student is asked to find the spring constant, k. After suspending a mass of 255.0 g from the spring, the student notices the spring is displaced 47.5 cm from its previous equilibrium. With this information, calculate the spring constant. spring constant: N/m When the spring, with the attached 255.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calcula the period of oscillation, T, neglecting the mass of the spring itself.

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Chapter1: Units, Trigonometry. And Vectors
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A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal
support. The student is asked to find the spring constant, k. After suspending a mass of 255.0 g from the spring, the student
notices the spring is displaced 47.5 cm from its previous equilibrium. With this information, calculate the spring constant.
spring constant:
N/m
When the spring, with the attached 255.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calcula
the period of oscillation, T, neglecting the mass of the spring itself.
T =
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Transcribed Image Text:V Hint A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal support. The student is asked to find the spring constant, k. After suspending a mass of 255.0 g from the spring, the student notices the spring is displaced 47.5 cm from its previous equilibrium. With this information, calculate the spring constant. spring constant: N/m When the spring, with the attached 255.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calcula the period of oscillation, T, neglecting the mass of the spring itself. T = about us privacy policy terms of use contact us help careers
In the final section of the lab, the student is asked to investigate the energy distribution of the spring system described
previously. The student pulls the mass down an additional 35.6 cm from the equilibrium point of 47.5 cm when the mass is
stationary and allows the system to oscillate. Using the equilibrium point of 47.5 cm as the zero point for total potential
energy, calculate the velocity and total potential energy for each displacement given and insert the correct answer.
Displacement (cm) from equilibrium Velocity (m/s) Total potential energy (J)
35.6
26.1
Answer Bank
1.62
0.334
1.10
0.594
0.180
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Transcribed Image Text:In the final section of the lab, the student is asked to investigate the energy distribution of the spring system described previously. The student pulls the mass down an additional 35.6 cm from the equilibrium point of 47.5 cm when the mass is stationary and allows the system to oscillate. Using the equilibrium point of 47.5 cm as the zero point for total potential energy, calculate the velocity and total potential energy for each displacement given and insert the correct answer. Displacement (cm) from equilibrium Velocity (m/s) Total potential energy (J) 35.6 26.1 Answer Bank 1.62 0.334 1.10 0.594 0.180 | help about us careers privacy policy terms of use contact us w
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