College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A person faces the possibility of receiving the following absorbed doses of
a) the X-rays
b) the alpha particles
c) the protons
d) They will produce the same damage.
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- A tumor is exposed to a beam of protons containing 2.6 × 1010 protons. If 25% of the beam energy is absorbed in a tumor of mass 1.25 kg, what is the dose equivalent in the tumor? Each proton has an energy of 52 MeV, and the RBE of this type of radiation is 32. a) 0.043 Sv b) 1.38 Sv c) 4.3 Sv d) 13.8 Sv e) 37 Svarrow_forward11. A 60 kg person accidentally ingests a small source of alpha particles (RBE=15). The activity of the source is 0.04 Ci, the half life of the source is 110 years, and each alpha particle emitted has an energy of 0.586MEV. It takes 12 hours for the alpha source to pass through the persons digestive system and exit the body. (a) How many alpha particles are absorbed by the person (you may assume that 100% of the alpha particles emitted by the source are absorbed by the person)? (b) How much energy is deposited in the person by the source (in J)? (c) What is the absorbed dose (in rad)? (d) What is the absorbed dose (in rem)?arrow_forwardThe table gives the data the scientist obtained when she tested 1 kg of cooked A scientist has compared the vitamin content of food exposed to gamma radiation (c) with food that has not been exposed. chicken. Food not exposed to gamma radiation Food exposed to gamma radiation Vitamin Mass in milligrams Mass in milligrams B6 1.22 1.35 B12 21.00 28.00 E 3.30 2.15 Niacin 58.00 55.50 Riboflavin 2.10 2.25 Considering only this data, which one of the following is a correct conclusion? Put a tick (v) in the box next to your answer. Vitamin content is not affected by gamma radiation. Gamma radiation completely destroys some types of vitamin. Exposure increased the content of some types of vitamin. (1) (Total 6 marks)arrow_forward
- 7. One of the many isotopes used in cancer treatment is 198 Au, with a half-life of 2.70 d. Determine the mass of this isotope that is required to give an activity of 225 Ci. mg VJSS f60 ssf ( sf60 ssfarrow_forwardA 60 kg radiation worker accidently ingest 1.0 mg of Po211. Assume that Po211 resides in the body of the person in 1 second and all emitted alpha particles are stopped within the body. a) Calculate Number of Po211 atoms ingested. b) Calculate the number atoms that decayed during 1 second. c) Calculate the total energy absorbed. d)Calculate the total dose. e) Calculate the equivalent dose. (RBE= 20). f) Make a commend about your result.arrow_forwardPlease answer correctlyarrow_forward
- 58. . Radiation treatment of prostate cancer. In many cases, BIO prostate cancer is treated by implanting 60 to 100 small seeds of radioactive material into the tumor. The energy released from the decays kills the tumor. One isotope that is used (there are others) is palladium (10°Pd), with a half-life of 17 days. If a typical grain contains 0.250 g of 10°Pd, (a) what is its initial activity rate in Bq, and (b) what is the rate 68 days later?arrow_forwardA person with lymphoma receives a dose of 35 gray in the form of gamma radiation during a course of radiotherapy. Most of the dose is absorbed in 18grams of cancerous lymphoma tissues. i. How much energy is absorbed by the cancerous tissue. ii. If this treatment consist of five 15 minutes session per week and just one percent of the gamma photon in the gamma ray beam are absorbed. What is the power of the gamma ray beam. iii. If the gamma ray beam consists of just 0.5 percent of the photons emitted by the gamma ray source, each of which has an energy of 0.03 Mev. What is the activity in curries of gamma ray source.arrow_forward
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