A particle's position with respect to time as it moves along a coordinate axis is given by the function p(t)=3t^3−t^2−t+2. What is the particle's acceleration function a(t)?
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A particle's position with respect to time as it moves along a coordinate axis is given by the function p(t)=3t^3−t^2−t+2. What is the particle's acceleration function a(t)?
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- A particle moving along the x-axis has velocity function v(t) = t³ sin t. How far does the particle travel from time t = 0to t = π?A particle moves according to the function, r → ( t ) = ( t 3 − 4 ) i ^ + ( 2 t 2 + 2 t ) j ^where r → is measured in meters. a) What is this particle's instantaneous acceleration at t = 2 seconds? b) What is the particle's y coordinate when its x coordinate is equal to zero? Please consider only positive values for the time.A particle's position with respect to time as it moves along a coordinate axis is given by the function p(t)=t3+2t−2. What is the particle's acceleration at time t=−1?
- The position x of a particle in motion, as a function of time t, is given by: x = 3t 2- 2t %3D + 2. The instantaneous velocity at t = 3s is +12 m/s +20m/s O +18 m/s O +14 m/s +16 m/s(The complete question is in the picture) A particle’s position r in time t was shown to be:r(t) = (t + sin t)ˆi + (t)ˆj + (2.00 [m]) kˆ.What is it’s velocity v and acceleration a at t = 5.00 [s]?A. v = (1.00 [m/s])ˆj,a = (0.0871 [m/s2])ˆiB. v = (1.28 [m/s])ˆi+(1.00 [m/s])ˆj,a = (0.959 [m/s2])ˆiC. v = (2.00 [m/s])ˆi−(0.09 [m/s])ˆj,a = (−0.959 [m/s2])ˆiD. v = (0.72 [m/s])ˆi+(1.00 [m/s])ˆj,a = (−0.959 [m/s2])ˆiA particle moves along an s-axis with position function s=s(t) and velocity function v(t)=s′(t). Use the given information to find s(t). v(t)=4e^t,s(1)=0 s(t)=?????????
- Problem 9: A particle moving along a straight line with constant acceleration has a velocity of 1.7 m/s at t = 3.97 s, and a velocity of -4.53 m/s at t = 5.21 s. What is the particle's acceleration in m/s²? sin() cos() tan() 8 9 HOME cotan() asin() acos() E 6 atan0 acotan( cinh0 1.A particle moving along the xx-axis has its position described by the function x=(4t3+5t+2)mx=(4t3+5t+2)m, where t is in s. At t = 2 s, what is the particle's position?WRITE THE ANSWER IN 10 MINUTES PLEASE ! ! ! A particle is moving in three dimensions and its position vector is given by; r(t)= (3t^2+3.5t)i + (2.5t−4.8)j+ (2.8t^3+4.5t)k where r is in meters and ?t is in seconds. Determine the magnitude of the instantaneous acceleration at t=3s. Express your answer in units of m/s2 using one decimal place.
- A particle moving vertically according to the equation of motion s(t) = gt + bt, where b > 0 and g is the acceleration due to earth's gravity, is moving up when b. te 0, 2g () O True O FalseAn object's position as a func of time is given by ; x(t) = - 200 (( t + 1 ) ^ - 1) + 6t^2. (Assume constants have proper SI Units) What are the object's instantaneous velocity at t = 3.00 seconds ? Answer = 48.5 m/sA particle trajectory is described by x= ( 0.7t -5. 7 t ) m, and y=(1t -4.4 t) m. where t is in seconds. red (1) what is the position of the particle at t = 4.2 s 3.0 tion (2) what is the velocity of the particle at t = 4.2 s )j m/s (3) What is the speed of the particle at t = 3 s m/s us page abus Summary Jump to...