A particle starts at rest and moves in a straight line with acceleration a =any constants from integration.)The velocity of the particle as a function of time is v(t) =The velocity of the particle at t = 9 seconds is v(9)The position of the particle at time t is s(t) =coefficients.The position of the particle at time t = 9 is s(9) =-2t+1 m/s². (Note: Omitm/sm/sm. Include 3 significant digits in themAdd WorkSubmit Questionesc90000000F1F2Ma

Given, a=-2t+1 m/s^2Velocity of particle as a function of time:we know…

Answered: A particle starts at rest and moves in…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A point moves in a circle at a constant speed of 35cm/sec. The period of one complete journey around the circle is 20sec. At t = 0 the line to the point from the center of the circle makes an angle of 30° with the x axis. a) Obtain the equation of the x coordinate of the point as a unction of time, in the form x = A cos (ωt + φ), giving the numerical values of A, ꞷ and φ. b) What are the values of x, dx/dt, and d2x/dt2 at t = 4 sec.
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A particle is moving in three dimensions and its position vector is given by; r→(t)=(1.6t^2+3.7t)i+(3.7t−1.4)j+(4.6t^3+3.8t)k where r is in meters and ?t is in seconds. Determine the magnitude of the average acceleration between t=0s and t=2s. Express your answer in units of m/s2 using one decimal place.
The position of a particle along the positive x-axis is given by the following function r = 1t3 +14t2 +4, find the speed of the particle at time t=17, where t is in seconds and r is in cm. Recall that the velocity can be found by taking the derivative of the position vector. Express your answer in cm/s.
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