A particle is traveling in a straight line. Its position at time t in seconds is given by s(t) = 8√t meters. (a) The instantaneous velocity at time t is given by v(t) = (b) The acceleration at time t is given by a(t) = (c) At time t = velocity of acceleration is 9 seconds, the particle is going at a meters per second. The meters per second square.

A particle moves so that its position (in meters) as a function of time (in seconds) is r = î + 5t2 j + 5t k. (Use the following as necessary: t.) (a) Write an expression for its velocity as a function of time. V = m/s (b) Write an expression for its acceleration as a function of time. a = m/s?

Given that the position of a particle is defined in terms of time by the equation below, where x is in meters and t is in seconds, determine: 4t3 + t² 3t2 + + 4 t (a) the average velocity of the particle from t = 1.0 s to t = 3.0 s, (Ans: vave = 16 m/s) (b) the instantaneous velocity of the particle at t = 2.5 s, (Ans: vx = 20.52 m/s) (c) the average acceleration of the particle from t = 2.0 s to t = 3.0 s, and (Ans: aave = 8.42 m/s2) (d) the t at which the instantaneous acceleration of the particle is 8.10 m/s2. (Ans: t = 3.91 s)

An object's position as a function of time in one dimension is given by the expression; 3.89t2 + 2.22t + 7.48 where are constants have proper SI Units. What is the object's average velocity between the times t = 3.16 s and t = 8.38 s? with everything in 3 sig figs