College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![### Chapter 11, Problem 022
A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector \(\ \vec{r} = (2.00 \, \text{m}) \hat{i} - (3.00 \, \text{m}) \hat{j} + (2.00 \, \text{m}) \hat{k} \), the force is \(\ \vec{F} = F_x \hat{i} + (7.00 \, \text{N}) \hat{j} - (6.00 \, \text{N}) \hat{k} \), and the corresponding torque about the origin is \(\ \vec{\tau} = (4.00 \, \text{N} \cdot \text{m}) \hat{i} + (10.0 \, \text{N} \cdot \text{m}) \hat{j} + (11.0 \, \text{N} \cdot \text{m}) \hat{k} \). Determine \( F_x \).
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Transcribed Image Text:### Chapter 11, Problem 022
A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector \(\ \vec{r} = (2.00 \, \text{m}) \hat{i} - (3.00 \, \text{m}) \hat{j} + (2.00 \, \text{m}) \hat{k} \), the force is \(\ \vec{F} = F_x \hat{i} + (7.00 \, \text{N}) \hat{j} - (6.00 \, \text{N}) \hat{k} \), and the corresponding torque about the origin is \(\ \vec{\tau} = (4.00 \, \text{N} \cdot \text{m}) \hat{i} + (10.0 \, \text{N} \cdot \text{m}) \hat{j} + (11.0 \, \text{N} \cdot \text{m}) \hat{k} \). Determine \( F_x \).
**Input Fields:**
- **Number:** [Text Box]
- **Units:** [Dropdown Menu]
*The tolerance is +/- 5%*
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**Question Attempts:** 0 of 10 used
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