A particle has a charge of +2.2 μC and moves from point A to point B, a distance of 0.29 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +9.2 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

A particle has a charge of +1.40 µC and moves from point A to point B, a distance of 0.170 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA- EPEB = +8.20 x 104 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

A particle with a charge of q = 12.0 µC travels from the origin to the point (x, y) = (20.0 cm, 50.0 cm) in the presence of a uniform electric field E = 210î V/m. Determine the following. (a) the change in the electric potential energy (in J) of the particle-field system (b) the electric potential difference (in V) through which the particle moves V

A small object with a charge of q = 12.0 µC travels from the origin to the point (x, y) = (20.0 cm, 50.0 cm) in the presence of a uniform electric field E = 2701 V/m. Determine the following. (a) the change in the electric potential energy (in J) of the object-field system (b) the electric potential difference (in V) through which the object moves V Need Help? Read It

The drawing shows a square, each side of which has a length of L = 0.250 m. Two different positive charges 9₁ and 92 are fixed at the corners of the square. Find the electric potential energy of a third charge q3 = -6.00 x 10-9 C placed at corner A and then at corner B. B 91 = +1.50 x 10-⁹ c A 42 = +4.00 × 109c

The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is |q| = 8.6 μC, and the distance between them is d = 3.8 mm. Determine the magnitude of the net force on charge 2 for each drawing. Calculate the electric potential energy with configuration of charges on the figures.

A point charge of 3nC with a mass of 4g is moved from x=1.0 m to x=1.5 m in an electric field of 5 N/C with the same direction as the motion of the charge. Identify the (a) amount of work done on the charge by the electric force, (b) change in potential energy of the charge, and (c) speed of the charge at x=1.5 m, assuming that it started from rest.

Point charges q1 = +2.00 C and q2 = -2.00 C are separated by 20.0 cm forming an electric dipole. The dipole is in a uniform external electric field E. The angle between E and the electric dipole moment vector p is 150 degrees. The magnitude of the torque on the dipole is 6.00 N·m. What is the electric potential energy of the dipole (in joules)?

A particle has a charge of +1.20 μC and moves from point A to point B, a distance of 0.240 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA-EPEB= +9.40 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences. (a) Number i (b) Number i Units Units

Two tiny metal spheres A and B of masses mA = m and mB = have equal positive charges q. The spheres are connected by a massless nonconducting string of length d, which is much greater than the radii of the spheres. NOTE: Express your answers in terms of m, q, d, and eg. (a) What is the electric potential energy of the system? U = (b) Suppose you cut the string. At that instant, what is the acceleration of sphere A? AA = (c) Suppose you cut the string. At that instant, what is the acceleration of sphere B? Ав (d) A long time after you cut the string, what is the speed of sphere A? VA = (e) A long time after you cut the string, what is the speed of sphere B? UB =