The figure below shows a small, charged sphere, with a charge of q = +45.0 nC, that moves a distance of d = 0.168 m from point A to point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right. (a) What is the magnitude (in N) and direction of the electric force on the sphere? (b) What is the work (in J) done on the sphere by the electric force as it moves from A to B? (c) What is the change of the electric potential energy (in J) as the sphere moves from A to B? (The system consists of the sphere and all its surroundings.) PEB − PEA = (d) What is the potential difference (in V) between A and B? VB − VA =
The figure below shows a small, charged sphere, with a charge of q = +45.0 nC, that moves a distance of d = 0.168 m from point A to point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right. (a) What is the magnitude (in N) and direction of the electric force on the sphere? (b) What is the work (in J) done on the sphere by the electric force as it moves from A to B? (c) What is the change of the electric potential energy (in J) as the sphere moves from A to B? (The system consists of the sphere and all its surroundings.) PEB − PEA = (d) What is the potential difference (in V) between A and B? VB − VA =
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 1CQ
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The figure below shows a small, charged sphere, with a charge of q = +45.0 nC, that moves a distance of d = 0.168 m from point A to point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right.
(a)
What is the magnitude (in N) and direction of the electric force on the sphere?
(b)
What is the work (in J) done on the sphere by the electric force as it moves from A to B?
(c)
What is the change of the electric potential energy (in J) as the sphere moves from A to B? (The system consists of the sphere and all its surroundings.)
PEB − PEA =
(d)
What is the potential difference (in V) between A and B?
VB − VA =
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