A parallel-plate capacitor has a capacitance of 10 mF and is charged with a 20 V power supply. The power supply is then removed and a dielectric of dielectric constant 4 is used to fill the space between the plates. The voltage now across the capacitor is

A parallel plate capacitor has a capacitance of 5.5 µF when filled with a dielectric. The area of each plate is 2.0 m2 and the separation between the plates is 0.84E-5 m. What is the dielectric constant of the dielectric?

When capacitor A holds a charge of 50C, the potential difference between its plates is 25 volts. When capacitor B holds a charge of 5 C, the potential difference between its plates is 0.1 volts. Which capacitor has the greatest capacitance?

An air filled capacitor C= 10uF is connected to a 15V battery. The capacitor is disconnected from the battery and the distance between the plates is doubled. What is the energy stored in the capacitor now?

An initially uncharged air-filled capacitor is connected to a 3.29 V charging source. As a result, the capacitor acquires 9.89 x 10- C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant k of this substance is 7.61. Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is inserted and the circuit has returned to a steady state. V = V Qt = C

A parallel plate capacitor has a capacitance of 0.20 μF. The capacitor is notconnected to a battery or a power supply. There is a charge of 24 μC on thecapacitor. How much work must be done on the capacitor to double the separation between the plates?

There are two parallel plate capacitors. They each have plates with areas of 2.3 meters squared, and plate separations of 9 mm. The first capacitor has a dielectric with a dielectric constant of 18 and the second has a dielectric with a dielectric constant of 19. What is the capacitance of these two capacitors in parallel with each other? Give your answer in microfarads.

In a parallel-plate capacitor, the two plates each have an area of 0.460 m2 and are spaced 3.00 mm apart.The capacitor is charged to a voltage of 4.00 kV using a power source that is then removed. The gap between the plates is then filled by a dielectric layer. The charge on each plate stays constant at 2.50 kV despite the reduction in the potential difference between the plates.Calculate the initial capacitance value of the system.

The capacitance of an empty capacitor is 1.2 μF. The capacitor is connected to a 12-V battery and charged up. With the capacitor connected to the battery, a slab of dielectric material is inserted between the plates. As a result, 2.6 × 10–5 C of additional charge flows from one plate, through the battery, and onto the other plate. What is the dielectric constant of the material?