A simple curve with tangents AV and VE have azimuth of 260°48' and 285°40' respectively. Point B is taken along AV and C along VE. Theazimuth and distance of BC are 272°16' and 61.22 m respectively. The degree of curve is 5°. The stationing of point B is 8 + 126.3.1. Determine the radius of the simple curve.a. 184.99 mb. 229.18 mc. 314.67 md. 287.25 m2. Determine the length of curve.a. 99.47 mb. 85.45 mc. 51.93 md. 79.12 m3. Determine the stationing of PT.a. 8 + 155.21b. 8 + 208.98c. 8 + 311.63d. 8 + 194.47

The question is based on a simple curve with two tangents. The azimuth of tangents and the degree of…

Answered: A simple curve with tangents AV and VE…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

2. The forward and the backward tangents of a simple curve, have an azimuth of 239°15' and 180°45’ respectively. The distance from the middle of the chord to the vertex is 57.73 m. And the stationing of the vertex is 2+022.162. a) Determine the radius of the curve. b) Determine the stationing of P.C. c) Determine the stationing of P.T.
A COMPOUND CURVE is composed of three simple curves (CURVE1, CURVE2 & CURVE3).Compute the stationing of PT if the stationing of PC is 6 + 623.56.CURVE1 Radius = 1,157.40 metersCURVE1 Long Chord = 470.80 metersCURVE2 Radius = 550 metersCURVE2 Long Chord = 185.50 metersCURVE3 Radius = 467.87 metersCURVE3 Long Chord = 153.75 meters
A 5 degree circular turnout is to connect a railway track, leading due east, to the mouth of the tunnel which is 70m. from the station 7+812. Use Chord Basis. Determine the radius of the curve in meters. Ans. 229.30
A simple curve connects two tangents AB and BC with bearings N 36°12' E and N 58°53' E respectively. The PC is a A which is at Sta. 5+234.65 and the B is at Sta. 5+265.09. * Find the radius of the curve. a. 169. 09 m c. 201.12 m b. 137.85 m d. 151.76 m * Using chord basis, compute the degree of the curve. c. 6.78° a. 5.70° b. 7.56° d. 8.31° * Find the external distance. c. 3.36 m a. 2.75 m b. 3.02 m d. 4.01 m * Find the middle ordinate. c. 2.69 m a. 2.96 m b. 3.93 m d. 3.30
the two-centered compound curve has centers at 01, 02 with central angle equal to. A1, A2. Given R1 = 220 m and R2 = 290 m and A1 = 152°13' , A2 =47°12' and Pl station 1+000 Draw a neat drawing for compound curve Find Ta and Tb and station value BC1, EC1, BC2, and EC2 by using Traverse method and repeat the same calculation by using vertex methods
1. From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths 300 (forward tangent) and bearing N 04 E (back tangent), respectively. A common tangent line CD intersects the two tangent lines at bearing S 34° E. Stationing of the vertex of the compound curve is 16+ 464.35 and the distance from point D to the vertex of the compound curve is 137.6 m. If the external distance of the curve passing through the PC is 1.42 times the external distance of the simple curve that passes through the PT, solve for the following. a. Radius of the curve that passes through the PC b. Radius of the curve that passes through the PT c. Stationing of the PT
TOPIC: Surveying (Horizontal Curves)
4. A parallel reversed curve has an equal radius of 360m and a central angle of 8º. a. Compute the distance between parallel tangents b. Compute the length of the Chord from PC to PT If Sta PC = 3 +960.40, what is Sta PT? C.
Calculate the chainage of the tangent points of the compound curve from the following: Stat. P.I=28+50 R1=500m. Ø1 = 38° 20' R2=750m. Ø2 = 41° 30'
The forward and the backward tangents of a simple curve, have an azimuth of 239°15’ and 180°45’ respectively. The distance from the middle of the chord to the vertex is 57.73 m. And the stationing of the vertex is 2+022.162. a) Determine the radius of the curve b) Determine the stationing of P.C. c) Determine the stationing of P.T.
2. The common tangent CD of a reversed curve is 354.21 m and has an azimuth of 312°29'. BC is a tangent of the first curve whose azimuth is 252°45'. DE is a tangent of the second curve whose azimuth is 218°13'. The radius of the first curve is 180 m. The PI(1) is at Sta. 16+523.37. B is at PC and E is at PT. a) What is the Station of PC? b) What is the Station of PRC? c) What is the Station of PT?
The backward tangent of +5% and a forward tangent of -3% is connected by a vertical symmetrical parabolic summit curve of length 200m. а. Determine the radius of the curve.

Recommended textbooks for you

Structural Analysis

Civil Engineering

ISBN:

9781337630931

Author:

KASSIMALI, Aslam.

Publisher:

Cengage,

Structural Analysis (10th Edition)

Civil Engineering

ISBN:

9780134610672

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Principles of Foundation Engineering (MindTap Cou…

Civil Engineering

ISBN:

9781337705028

Author:

Braja M. Das, Nagaratnam Sivakugan

Publisher:

Cengage Learning

Structural Analysis

Civil Engineering

ISBN:

9781337630931

Author:

KASSIMALI, Aslam.

Publisher:

Cengage,

Structural Analysis (10th Edition)

Civil Engineering

ISBN:

9780134610672

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Principles of Foundation Engineering (MindTap Cou…

Civil Engineering

ISBN:

9781337705028

Author:

Braja M. Das, Nagaratnam Sivakugan

Publisher:

Cengage Learning

Fundamentals of Structural Analysis

Civil Engineering

ISBN:

9780073398006

Author:

Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning

Publisher:

McGraw-Hill Education

Sustainable Energy

Civil Engineering

ISBN:

9781337551663

Author:

DUNLAP, Richard A.

Publisher:

Cengage,

Traffic and Highway Engineering

Civil Engineering

ISBN:

9781305156241

Author:

Garber, Nicholas J.

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS