A normal population has mean µ = 7 and standard deviation o = 5. (a) What proportion of the population is less than 19? (b) What is the probability that a randomly chosen value will be great Round the answers to four decimal places. Part 1 of 2 The proportion of the population less than 19 is X

Part C

11 Scores on a dental anxiety scale range from zero (no anxiety) to 20 (extreme anxiety). The scores are normally distributed distributed with a mean of 11 and a standard deviation of four. Find the Z score for the given score on this dental anxiety scale. 5 z5= ____ (Type an integer or a decimal)

2448 You'd like to test the null hypothesis that the means of the two samples (column A and column B) are the same. The alternative hypothesis is that they are not the same. You have no reason to believe that the standard deviations of the two samples are equal.  Test at the alpha = 0.10 level.   After using Excel, what do you conclude? Are the means the same? Group of answer choices You cannot reject the null hypothesis. Therefore, you conclude that the means of the two populations are different. You reject the null hypothesis. Therefore, you conclude that the means of the two populations are the same. You reject the null hypothesis. Therefore, you conclude that the means of the two populations are different. You cannot reject the null hypothesis. Therefore, you conclude that the means of the two populations are the same.   X1 X2 102.04 96.13 100.47 97.63 103.17 95.42 95.09 104.41 103.81 102.08 95.36 103.33 103.38 112.25 100.26 96.93 97.24 100.19 99.61…

X Question 13 Let X be a continuous random variable. Let's denote the p-th percentile of X as p%. For what value a, 160% = IQ? α = 0.60 X (Round the answer to 2 decimal places)

question 1 and 2

#21

Test scores carry a mean of 550 and a standard deviation of 125 normally distributed.  What proportion of the population exceeds 700?  Round to at least 4 decimal places.     How do I set this problem up and what steps do I need to take to solve it?  Please help, I am stuck!   Thank you!