A newspaper published an article about a study in which researchers subjected laboratory gloves to stress. Among 237 vinyl gloves, 59% leaked viruses. Among 237 latex gloves, leaked viruses. Using the accompanying display of the technology results, and using a 0.05 significance level, test the claim that vinyl gloves have a greater virus leak rate than late gloves. Let vinyl gloves be population 1. Click the icon to view the technology results. What are the null and alternative hypotheses? OA. Ho: P1 P2 H₁: P1 P2 OD. Ho: P1 P2 H₁: P₁ P2 OB. Ho: P1 P2 H₁: P₁ P2 OE. Ho: P₁ P2 H₁: P₁ P₂ OC. Ho: P1 P2 H₁: P₁ P2 OF. Ho: P1 H₁: P₁ P2 P2

According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 320 community college students at random and finds that 135 of them have a smart phone. In testing the hypotheses: Ho: p = 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4. 1. This is an example of a hypothesis test. 2. Find the standard error. 3. Find the z value. 4. Find the p-value. 5. The communication professor should the null hypothesis.

A large clinical trial of the effect of diet on breast cancer assigned women at random to either a normal diet or a low-fat diet. To check that the random assignment did produce comparable groups, we can compare the two groups at the start of the study. Asked if there is a family history of breast cancer: 1276 of the 5964 women in the low-fat group and 1507 of the 7726 women in the control group said "Yes." If the random assignment worked well, there should not be a significant difference in the proportions with a family history of breast cancer. How significant is the observed difference? State: Is there evidence of a difference in the proportion of women with a family history of breast cancer between the treatment and control groups? Plan: Let pi be the proportion for the treatment group, and Pz the proportion for the control group. State the hypotheses for your test. Ha:Pi + P2 Solve: Give the value of the test statistic. Use the calculator. Select an answer ♥ Ho:pi = p2 What is the…

According to a recent poll, the percentage of Americans who would vote for the incumbent president is 53%. If a random sample of 100 people in New York results in 45% who would vote for the incumbent, test the claim that the percentage of people in New York who would vote for the incumbent president is different from 53%. Use the following results and a 0.10 significance level to state your decision about  H0. H0 : p=0.53 H1 : p≠0.53 test statistic: z = -1.6 p value = 0.1090

One study claimed that 88 % of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 272 college students and finds that 231 of them identify themselves as procrastinators. Does this evidence support the professor's claim that fewer than 88 % of college students are procrastinators? Use a 0.02 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho p = 0.88 Ha P 0.88

A psychologist is interested in people’s assessment of life happiness and how it relates to positive lifestyle changes. The researcher randomly assigns 42 individuals to one of two groups: Exercise Only, and Exercise and Healthy Eating. The researcher believes that Group 1 (n = 21; Exercise and Healthy Eating) will be significantly happier than Group 2 (n = 21; Exercise Only). Perform the correct test of significance, with alpha = .05. Be sure to write out your hypotheses and final decision.

According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 323 community college students at random and finds that 134 of them have a smart phone. In testing the hypotheses: Ho: p= 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for # 3 and #4. 1. I 4. Find the p-value.-- 5. The communication professor should the null hypothesis.

A new treatment for a certain disease is claimed to be effective in more than 80 % of cases . To test this claim the treatment was given to 100 randomly selected patients . The treatment was effective in 85 out of the 100 patients . What is the conclusion at a 5 % level of significance ? A.  Reject the null hypothesis .There is sufficient evidence to claim that the treatment is effective in more than 80 % of cases B.  Reject the null hypothesis .There is not sufficient evidence to claim that the treatment is effective in more than 80 % of cases C.  Fail to reject the null hypothesis. There is sufficient evidence to claim that the treatment is effective in more than 80 % of cases D.  Fail to reject the null hypothesis. There is not sufficient evidence to claim that the treatment is effective in more than 80 % of cases