College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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M12 LAB
Compute and Illustrate please.
A narrow beam of light is incident on one surface of a plane parallel plate of glass. The index of which is 1.62 and has a thickness of 5 cm at an angle of 45 degrees to the normal, trace the path of light through the plate. What will be the direction of the emergent light if the second surface of the glass is immersed in an oil wich an index of 1.49
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- 6. A sheet of glass has an index of refraction nalass = 1.45. Assume that the index of refraction for air is na= 1.00, Light is incident on the sheet of glass at an angle of incidence of 60°, as shown in the figure below. a. Calculate and label the size of each angle (in degrees) on the figure, including angles of incidence and refraction at each of the two parallel surfaces shown. 60 degrees Air na = 1.00 Glass " = 1.45 Air ng = 1.00 b. Calculate the velocity of the light as it travels in the glass.arrow_forwardCalculate the angle of refraction at the air/core interface, r . critical angle, c and incident angle at the core/cladding interface, i . Will this light ray propagate down the fiber? You have the following data: nair = 1, ncore = 1.46, ncladding =1.43, incident =12o r = 8.2o, c = 78.4o, i = 81.8olight will propagate Formula summery Index of Refraction n= n sin 01= n, sin 0, o = sin1(2) Snell's Law Critical Angle Acceptance angle a= sin1 Numerical Aperture NA = sin a = ni- nịarrow_forwardLight enters a substance from air at 45.0° to the normal. It continues within the substance at 25.0° to the normal. What is the critical angle for this substance when it is surrounded by air? 25.2° O Othere is no critical angle O O 60.3° 90.0° 36.8° 45.2°arrow_forward
- The Rayleigh criterion provides a convenient way to describe the theoretical resolution (e.g. an ability to distinguish objects ) of an optical system. The criterion states that two small bright sources of light can be resolved if the first d mìnimum of the image of one source point just coincides with of further apart then the first maximum of another (s Ho Your c below). A converging lens, 28.7 mm in diameter, is used to form images of distant objects. Considering the diffractio lens, what angular separation must two distant point objects have in order to satisfy Rayleigh's criterion? Assume t Here wavelength of the light from the distant objects is 469 nm. Provide your answer in millidegrees (mdeg). STE Exp complexity subscibers Answer: Choose... + Check Finishin Check carrow_forwardLight enters a container of liquid at an angle of 49° to the normal; the refracted beam makes an angle of 29° with the normal. Calculate the index of refraction of this liquid. Group of answer choices 1.96 1.44 1.56 1.78arrow_forwardNeeds Complete typed solution with 100 % accuracy.arrow_forward
- In the above figure, theta (the angle the incident ray makes with respect to the vertical) is 26.0 degrees. What is d (the distance between the ray emerging from the bottom of the glass and where the ray would have been if it had continued straight on with no glass to refract it)?arrow_forwardconsider the following given. A red laser travelled from air (with an index of refraction of nair = 1.00) to medium A then to medium B as shown below.1. Considering that medium B has an index of refraction of nB = 2.42, what is the angle of refraction ϴ3 (when the laser emerged into medium B) if the angle of incidence is ϴ1 = 60o ?a. 0.35ob. 2.79oc. 21.0od. Not enough information2. From the figure, which of the following statements is true across the three media?a. light travels the slowest in airb. light travels faster in medium A than in medium Bc. light travels the fastest in medium Bd. light travels faster in medium A than in air.arrow_forwardFig. 1 shows a laser beam incident on a piece of wet filter paper placed on a glass plate whose 'refractive indexglass plate whose refractive index is to be measured (the rays are represented in the figure). Explain what happens anddeduce an expression for ni in terms of R and d. Consider the refractive index of air to be 1.Note: Remember that all light that falls on a reflecting surface always has part of the light reflected, being refracted or not.refracted or not. Moreover, θc in the figure represents the critical angle at which we have the condition of total internal reflectionarrow_forward
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