As we saw in the video in step 1, total internal reflection can occur for cases where a light ray attempts to travel from a high index to low index medium. However, it can only occur for particular ranges of incident angles. The lowest possible incident angle for which total internal reflection occurs is called the critical angle. With = 1.50 and n₂ = 1.00, use the simulation to find the critical angle (in degrees). 1₂ Play around with different values of n₁, 7₂, and 8₁. Try to find the critical angle for different values of n₁ and n₂. Note that total internal reflection is only possible in cases where n₁ > ₂. 1'

At the very end of Wagner's series of operas Ring of the Nibelung, Brünnhilde takes the golden ring from the finger of the dead Siegfried and throws it into the Rhine, where it sinks to the bottom of the river. Part A Assuming that the ring is small enough compared to the depth of the river to be treated as a point and that depth of the Rhine where the ring goes in is 12.8 m, what is the area of the largest circle at the surface of the water over which light from the ring could escape from the water? Use 1.33 for the index of refraction of water. Express your answer in meters squared. A = —| ΑΣΦ ? m²

The class I'm taking is physics for scientists and engineers! I am completely stuck . please help. please post step-by-step solution to help me better understand . I have attached problem. Please view before answering. Thank you!

Diamond is known for being a particularly brilliant stone. The reason behind this is its peculiarly high index of refraction, n = 2.4. A ray of light within a diamond hits the diamond-air (n = 1) interface. Calculate the critical angle for diamond such that the ray be totally internally reflected. Critical angle for diamond-air interface = 0 Once you have determined this, compare the critical angle to the one in the figure below, which is for a glass-air interface? Knowing that glass has a smaller refractive index than diamond, which material will have a larger critical angle. n2=1 n1 =1.5 39° 90° 41.8° 45° 45° Difference between the cirtical angles between the diamond-air and glass-air interface is (report the absolute value of the difference) 0 What is the significance of this comparison with regards to the brilliance of diamond?

Please draw the scattering configuration

Light traveling through medium 3 (n3 = 2.4) is incident on the interface with medium 2 (n2 = 2.0) at angle θ. If light does enter into medium 2 but no light enters into medium 1 (n1 = 1.6), what can we conclude about the range of values for θ?